the width of a square whose side is x cm, is increased by 5 cm and its length is decreased by 4 cm. How varies the area of the rectangle formed regarding side x of the original square?
Hello to you both :)
Omi, Where did the 400 come from?
Old area = x^2
New area = \((x+5)(x-4) = x^2+x-20\)
So the area has increased by x-20 units squared.
Of course, if x-20 is negative then the area will be smaller. :)
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Hola a los dos :)
Omi, de dónde vino el 400 viene?
Área de Old = x ^ 2
Nueva área =\((x+5)(x-4) = x^2+x-20\)
Así que la zona se ha incrementado en x-20 unidades al cuadrado.
Por supuesto, si x-20 es negativa entonces el área será más pequeña. :)
