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-5x - 10 = 10  x = ?

\(\begin{array}{rcll} -5x-10 &=& 10 \qquad | \qquad +10\\ -5x &=& 10 +10\\ -5x &=& 20 \qquad | \qquad \cdot(-1)\\ 5x &=& -20 \\ 5x &=& -20 \qquad | \qquad :5\\ x &=& -\frac{20}{5} \\ x &=& -\frac{4\cdot 5}{5}\\ \mathbf{x} &\mathbf{=}& \mathbf{-4}\\ \end{array}\)

17+42/53-98

17+42/53-98 = -80.2075471698113208

The latitude value of Toronto is 43.70 degrees, and the longitude value is 79.40 degrees. The latitude value of Melbourne is -37.81 degrees, and the longitude value is 144.96 degrees. The two cities are degrees apart in latitude. The two cities are degrees apart in longitude.

Sorry my delta longitude is false.

\(\begin{array}{lcl} \Delta \lambda &=& 144.96^{\circ}E + 79.40^{\circ}W = 224.36^{\circ} \\ \Delta \varphi &=& 43.70^{\circ} -(-37.81^{\circ} ) = 43.70^{\circ} +37.81^{\circ} =81.51^{\circ} \end{array}\)

The two cities are degrees apart in latitude \(81.51^{\circ}\)

The two cities are degrees apart in longitude \(224.36^{\circ}\)

-5X-10=10

add ten to both sides

-5x=20

divide both sides by -5

x=-4

"Wow" what?? -concerned Ak Dude

1/12+7/9=63/72 ?

\(\begin{array}{rcl} \frac{1}{12} + \frac{7}{9}\\ &=& \frac{1}{12}\cdot\frac{3}{3} + \frac{7}{9}\cdot\frac{4}{4}\\ &=& \frac{3}{36} + \frac{28}{36}\\ &=& \frac{31}{36}\cdot\frac{2}{2}\\ &=& \frac{62}{72}\\ \end{array}\)

The latitude value of Toronto is 43.70 degrees, and the longitude value is 79.40 degrees. The latitude value of Melbourne is -37.81 degrees, and the longitude value is 144.96 degrees. The two cities are degrees apart in latitude. The two cities are degrees apart in longitude.

Toronto's Longitude is:79.40W

Melbourne's Longitude is:144.96E

Therefore they are 79.40 + 144.96=224.36 degrees apart

Toronto's latitude is:43.70N

Melbourne latitude is:-37.81S

Therefore they are 43.70 - (-37.81)=43.70 + 37.81=81.51 degrees apart.

Isnt it 999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

877÷54 with remainder.

\(\begin{array}{rcl} \frac{877}{54} &=& 16.2407407407\\\\ 16.2407407407 - 16 &=& 0.2407407407\\ 0.2407407407 \cdot 54 &=& 13\\ \end{array}\)

13 is the remainder

What is the measure of the supplementary angle of a 76 degreese angle?

Two Angles are Supplementary when they add up to 180 degrees

\(180^{\circ} - 76^{\circ} = 104^{\circ}\)

So C is right.

The latitude value of Toronto is 43.70 degrees, and the longitude value is 79.40 degrees. The latitude value of Melbourne is -37.81 degrees, and the longitude value is 144.96 degrees. The two cities are degrees apart in latitude. The two cities are degrees apart in longitude.

\(\begin{array}{lcl} \Delta \lambda &=& 144.96^{\circ} - 79.40^{\circ} = 65.56^{\circ} \\\\ \Delta \varphi &=& 43.70^{\circ} -(-37.81^{\circ} ) = 43.70^{\circ} +37.81^{\circ} =81.51^{\circ} \end{array} \)

The two cities are degrees apart in latitude \(81.51^{\circ}\)

The two cities are degrees apart in longitude \(65.56^{\circ}\)

what is 0 F in degrees Celsius?

\(T_C=\frac59(T_F-32) \qquad T_F=0 \ °F\\ T_C=\frac59(0-32) \\ T_C=\frac59(-32) \\ T_C=\frac{5\cdot (-32)}{9} \\ T_C=-\frac{5\cdot 32}{9} \\ T_C=-\frac{160}{9} \\ T_C=-17.7\overline{7} \ °C\\\)

what is 0 F in degrees Celsius? Tc=5/9(TF-32)

 Tc=5/9(TF-32)

C=5/9(0 - 32)

C=(5 X -32)/9

C=-160/9

C=-17.77777777778..........etc.

Thank you so much to everyone who answered! You were all really helpful!  ☺

Z sin^3(x) cos^5(x) dx

they then rewrite it as:

sin x (cos^5(x) - cos^7(x))

how?

sin^3(x) cos^5(x), all these alternate forms are the same:

sin(x) cos^5(x)-sin(x) cos^7(x),

sin^7(x) cos(x)-2 sin^5(x) cos(x)+sin^3(x) cos(x),

1/128 (6 sin(2 x)+2 sin(4 x)-2 sin(6 x)-sin(8 x)),

-1/256 i (e^(-i x)-e^(i x))^3 (e^(-i x)+e^(i x))^5

sin^3(x) cos^5(x)

they then rewrite it as:

sin x (cos^5(x) - cos^7(x))

how?

\(\begin{array}{lcl} \sin^3{(x)} \cos^5{(x)} && \\ = \sin{(x)}\cdot \sin^2{(x)}\cos^5{(x)} \qquad | \qquad \sin^2{(x)} = 1-\cos^2{(x)}\\ = \sin{(x)}\cdot [ {1-\cos^2{(x)}} ] \cdot \cos^5{(x)} \\ = \sin{(x)}\cdot [ {\cos^5{(x)}-\cos^2{(x)}\cos^5{(x)}} ] \qquad | \qquad \cos^2{(x)}\cos^5{(x)} = \cos^7{(x)}\\ = \sin{(x)}\cdot [ {\cos^5{(x)}-\cos^7{(x)}} ] \end{array}\)

what is energy of earth? (E=MC^2)=5.369 X 10^41 Joules

It would take the Sun 45,000,000 years to produce that much energy!!!!.

New Edited:

[p or(~p and q)] = ?

\([p \text{ or }( \text{~} p \text{ and } q)] = p + \bar{p}\cdot q = p+q= p \text{ or } q \)

\(\text{true }=1 \quad \text{false }=0 \qquad \text{ and } = "\cdot" \quad \text{ or } = "+"\\ \begin{array}{|r|r|r|r||r|} \hline p & q & \bar{p} & \bar{p} \cdot q & p+ \bar{p} \cdot q & p+q = p \text{ or } q \\ \hline 0 & 0 & 1 & 0 & 0 & 0\\ 0 & 1 & 1 & 1 & 1 & 1 \\ 1 & 0 & 0 & 0 & 1 & 1\\ 1 & 1 & 0 & 0 & 1 & 1\\ \hline \end{array}\)

What is 11/5 written as a mixed number?

11/5=2 1/5

what is energy of earth? (E=MC^2)=5.369 X 10^41 Joules

dunno

uhhhh 2

what does -2/3=-.66666666666666666667................................etc.

877÷54 with remainder

877/54=16 with a remainder of 13. You determine the remainder as follows:

16 X 54=864

877 - 864=13 the remainder.

5 + -3 – -4=2 + 4=6