2x - 3 < x + 2 ≤ 3x + 5
Let's solve this in pieces
2x - 3 < x + 2 subtract x from both sides ....add 3 to both sides
x < 5
And
x + 2 ≤ 3x + 5 subtract x, 5 from both sides
-3 ≤ 2x divide both sides by 2
-3/2 ≤ x
The solution comes from the intersection of these intervals........this is [ -3/2, 5 ) or, expressed another way....-3/2 ≤ x < 5
