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Multiply both sides of the equation by (X-1) to get

6=60 (x-1)        Multiply through

6 = 60x - 60    Add 60 to both sides

66 = 60 x        Divide both sides by 60

66/60 = x

Simplify:

x  = 11/10

Add 2x and -12 to both sides of the equation

-12=7x    then divide both sides by 7    x = -12/7

.100

You're welcome, kasper....

x^2 - 6x + 9  = (x - 3) (x - 3)   = (x - 3)^2

We need to know another side or angle if this is not a right triangle....or.....if it is a right triangle....are these two legs......one leg and a hypotenuse ???

thanks CPhill

sqrt[34^2 - 16^2] = sqrt[900]  = 30 ft

what is the value of x if 4^x = 8^6?

Since 8^6=2^6 X 4^6= (2^2)^3 X 4^6=4^3 X 4^6=4^9, therefore,

x=9

200/6 = 100/3   = 33 + 1/3

6 in = 1/2 ft....so...the area of each tile  =(1/2 ft)^2  = (1/4) ft^2

And

[324 ft^2] / [1/4 ft ^2] =  1296 tiles

And each row will have sqrt[1296]  = 36 tiles

Just put this number into the onsite clculator and hit " = "

It will display the scientific notation form

(3/4)% =  .75%  = .0075

So

.0075 *  75   = 0.5625

v =  [ 0.27m / s^2 ]  * [101 s ] = 27.27 m/ s

X+100=Y  (1)

Y²=X²+400  (2)    

Substitute (1) into (2) and we have

[ X + 100]^2  = X^2 + 400    simplify

X^2 + 200X + 10000  = X^2 + 400       subtract X^2 + 400 from each side

200X + 9600  = 0    subtract 9600 from both sides

200x = -9600     divide both sides by 200

x = -96/2  = -48

4^x = 8^6

This isn't so hard to solve, once we equate bases....note   4 = 2^2    and 8 = 2^3....so we have.....

[2^2]^x  = [2^3]^6

2^(2x)  = (2)^(18)       now....we can solve for the exponents

2x = 18       divide both sides by 2

x = 9

2x - 3 < x + 2 ≤ 3x + 5.    we neeed to solve this in pieces.....first...

2x - 3 < x + 2       add 3 to both sides, subtract x from both sides

x < 5

Then  ....we need to solve

x + 2 ≤ 3x + 5    subtract x, 5 from both sides

-3 ≤ 2x         divide both sides by 2

-3/2 ≤  x

So....the answer is :          -3/2 ≤  x  <  5

(144+9)/9=(144/9)+(9/9)=17

A line segment beginning point A(-2,5) and ending at B(6,-7) is drawn on a coordinate plane. Point C(0,2) is plotted on AB. What is the ratio of AC to BC?

Distance from A to C = sqrt[ (-2 -0)^2 + (5 - 2)^2]  = sqrt [ 4 + 9]  = sqrt(13)

Distance from B to C  = sqrt[ (6 - 0)^2 + ( -7 - 2)^2]   = sqrt [ 36 + 81]  = sqrt (117)

So  the ratio of AB to BC  = sqrt 13) / sqrt(117)   =  sqrt(13 / 117)   = sqrt( 1/9)   = 1/3

10,000=37500a^36     divide both sides by 37500

4/15    = a^36     take the positive and negative 36th root of both sides

plus/minus(4/15)^(1/36)  = a ≈ plus/minus 0.9639503980508483

Because its stupid

82....