All Answers 358460 Answers

I've spent many days and nights contemplating how to respond to this question, and I believe I have finally found the answer.

WINDOW.

I think I just blew my own mind.

Sorry!!. I meant $100,000/5=$20,000!!!. Can't even divide!.

Guest #1

Sorry! That is NOT going to work. Why? Remember, each CD cannot be more than $100,000/5=$25,000. Your last part of 7/25 X 100,000=$28,000?????.

I'm just gonna guess   3 + 4 + 5 + 6 + 7 = 25 

    3/25 x 100k in the 7 % account

4/25 x 100k in the 6% account

5/25 x 100k in the 5% account

6/25 x 100k in the 4% account

7/25 x 100k  in the 3% account

Just a quick guess...I don't feel like ACTUALLY figuring it out....

3 x 3 x 3 x 3 x 3 = 243

Well, I would include Jack in the head count for a total of 5 people    6 chips/5 people   =  1.2 chips each

~jc

Thats a play on words with my name bieng riddler and riddles!

Even the riddler doesn't know that riddle

Hi Riddler

Yes a good answer will get you at least 5 points, off yourself or me or CPhill .  (You can give yourself points for a good answer if you want).

How these points REALLY accumulate is one of life's riddles.  Only admin knows:)

Solve for x:
8/x-3 = 2-32/x

Bring 8/x-3 together using the common denominator x. Bring 2-32/x together using the common denominator x:
(8-3 x)/x = (2 (x-16))/x

Multiply both sides by x:
8-3 x = 2 (x-16)

Expand out terms of the right hand side:
8-3 x = 2 x-32

Subtract 2 x+8 from both sides:
-5 x = -40

Divide both sides by -5:
Answer: | x = 8
 

6/4= 1 1/2

Everyone should get 1 and a half a chip

Add 32/x to both sides of the equation to get:

40/x -3 =2   then add 3 to each side

40/x = 5   Multiply both sides by x to arrive at:

40 = 5x   then divide both sides by 5 to get.......?

X=8 b/c 8/8-3=-2 -32/8+2=-2

15/7=2.142857

Thanks and hello!

Did you know: 1 cubic cm of a neutron star material weighs as much as Mount Everest? It is a fact!!!.

1 inch=2.54cm=25.4mm

3/8=.375 X 25.4mm=9.525mm

A supplier sells 2 1/4 pounds of mulch for every 1 1/3 pounds of gravel. The supplier sells 172 pounds of mulch and gravel combined. How many pounds of each item does the supplier sell?

2.25 + 1 1/3=3.5833333 combined number of pounds of mulch and gravel sold.

2.25/3.583333 X 172=108 pounds of mulch that the supplier sells

(1 1/3) / 3.583333 X 172=64 pounds of gravel that the supplier sells.

Let 'x' = pounds of gravel        The ratio of mulch to gravel is given  2 1/4  /  1 1/3   Which equals  9/4  /  4/3     =   27/16

So the total gravel and much is equal to   x + 27/16x = 172 

Solving for 'x'

43/16 x = 172   

x = 172 (16/43) = 64 pounds of gravel           Mulch = 27/16x = 64 (27/16)= 108 pounds

In 2007, the U.S. population was 302 million people. In 2012, it was 314 million. What was the rate of population change per year?

314/302=1.039735 growth in US population in 5 years

(1.039735)^1/5=0.782% average growth in US population per year.

Here's the diagram.......

The inradius  will be located at (8,n)   where n is the y coordinate we are looking for....let's call this "O"

The equation of the line containing segment KL  is  y = 0

And the equation of the line that contains segment JK   is  y = (15/8)x →  15x - 8y = 0

And  "O" =  (8,n) will be equidistant from JK and KL

Using the "formula"    for the distance from a point to a line, we have

abs(15(8) - 8n)  / sqrt [ 15^2 + (-8)^2 ]      =  abs ( n )     

And we will assume that both n  and 15(8) - 8n > 0....so we have

[120 - 8n] / 17   = n     

[120 - 8n ] = 17n

120  = 25n

n = 120/25 =  24/5

And the distance ffrom this point to the line y = 0   is just 24/5........and this is the inradius

The equation of the incircle of triangle JKL  is   (x - 8)^2 + (y - 24/5)^2  = (24/5)^2

Thanks, Riddler........5 pts. from me.......!!!!

If you give a good answer to a question, you usually get 5 points from me......other members are able to give you points, too......

But.....don't worry about it too much.......it's just a " fun"   thing....

Mainly.....we're glad you joined, Riddler......Welcome  !!!!

may someone please help?

From the associated diagram below, it is obvious that the radius of the circle on which each of the vertices of triangle JKL lie will be located at (8, n)........where n is the y coordinate that we're looking for....let's call this point "O"

We can equate distances here to solve for n

The distance from K to O    =  sqrt [ 8^2 + n^2]   = sqrt [ 64 +n^2 ]

And the distance from  J to O   = sqrt  [ (15 - n)^2]  =  15 - n

So .......sqrt [ 64] + n^2] = 15 - n     ...... square both sides

64 + n^2  =  225 - 30n + n^2

30n  = 225 - 64

30n =  161

n = 161 / 30

So, "O"  =  (8, 161/30)

And the distance from J  to O   =  15 - 161/30   =  [450 -  161] / 30   =  289/30 .....  this is the circumradius......!!!

And the equation of the circle through all three points is :

(x - 8)^2 + (y - 161/30)^2   = (289/  30)^2

P.S.  = There is a "formula" for finding the circumradius of a triangle  =    [ a* b * c ] / [ 4 A]    where a,b,c are the sides of the triangle and A is the area......

Using this, we have   [ 16 * 17^2]  / [ 4 * 120]  = 289 / 30   .....the same result as mine  !!!!

Here's the proof of this "formula"...it's surprisingly simple !!!!........http://www.artofproblemsolving.com/wiki/index.php/Circumradius

Eighty million