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We still need a diagram or description of the triangle....is it a RIGHT triangle?  Isosceles?   The square is   9x9 = 81 sq ft

If it is a RIGHT triangle, AND those are the LEG measurements (not the longest side-the hypoteneuse)   then the area = 1/2 ( L x H) = 1/2 (9 x 6) = 27 sq ft  (sometimes written as ft^2)

~jc

This is much like a lot of the financial problems posted on this forum

m =number of months to reach 87

P= number of attendees now 

We need to find the equation that defines how long it will take to get to 87  (The future value  or Pf)

Pf = P ( 1 + i)^m = 87     i was given as 10 percent or 0.010   so  Pf = P(1.010)^m = 87         and  P was given as starting at 29

  87 = 29 (1.010)^m  

~jc

it is 144 you were 1 off

If you put this into standard Quadratic Equation form, you can use the Quadratic Formula to get your answer(s)

1.83m^2 - .13175m + .575 = 0        SOME people may be able to facto this in their head....I can't, so I would use the Quadratic Formula for this one

Then in the Quadratic Formula    a = 1.83   b = -.13175    and c = .575    Crunch it out with the Quadratic Formula and let me know what you find !  GO !

~jc

9ft by 9 ft is a square and 6 by 9 ft is a triangle

9ft by 9 ft is a square and 6 by 9 ft is a triangle

For Q #5

x = number of couples    Uh-OH   I think you neglected to tell us how many people attended !    

How many people attended ?   

~jc

For Q # 3

Let  x  = 100 bills       the rest are 50's   or  117 - x   is the number of 50s

the value of the 100's   is    x (100)      the value of the 50's is  50 (117-x)     when these values are added they total 9950

x (100) + 50 (117-x) = 9950     SOlve this for x

100x + 5850 - 50x = 9950

50x = 4100

x = 82  The number of 100s    117- x = 117 - 82 = 35   50s  

~jc

3.) A bank teller counted $100 and $50 bills. This totalled to 117 bills to worth $9950. How many bills of each type were there?

Let the number of $50=f

Let the number of $100=h,

f + h=117 and,

50f + 100h=9950

Solve the following system:
{f+h = 117 |     (equation 1)
50 f+100 h = 9950 |     (equation 2)
Swap equation 1 with equation 2:
{50 f+100 h = 9950 |     (equation 1)
f+h = 117 |     (equation 2)
Subtract 1/50 × (equation 1) from equation 2:
{50 f+100 h = 9950 |     (equation 1)
0 f-h = -82 |     (equation 2)
Divide equation 1 by 50:
{f+2 h = 199 |     (equation 1)
0 f-h = -82 |     (equation 2)
Multiply equation 2 by -1:
{f+2 h = 199 |     (equation 1)
0 f+h = 82 |     (equation 2)
Subtract 2 × (equation 2) from equation 1:
{f+0 h = 35 |     (equation 1)
0 f+h = 82 |     (equation 2)
Collect results:
Answer: | f=35      and        h=82
 

x = number of 25 cent coins, then according to the problem   ( x (2) -9 ) is defined as the number of 5 dollar coins

so the value of 25 cent coins is  x (25) cents and the value of 5 dollar coins is  500 (x(2) - 9) cents  and these two added together = 12925 cents

  (everything needs to be expressed in cents....makes 'cents' , huh?    Ha)

so:   x(25) + (  500(x(2)-9)) = 12925   now solve for 'x'   (the number of 25 cent coins)

25x + 1000x - 4500 =12925

1025 x = 17425

x = 17 = number of 25 cent coins      Two times this and subtract 9 to get 5 dollar coins  =    2(17)-9 = 25   5 dollar coins

~jc

x=2

2.) Mister Adam sells tapioca pearls in 4 kilo and 3 kilo containers. With much demand for the tapioca pearls, he sold 30 containers weighing 300 kilos. How many of each type did he sell?

I think there maybe something wrong with your question: he cannot sell 30 containers weighing 300 kilos, because 300/30=10 kilos. But he only has cans that weigh 4 and 3 kilos!. So, even if he sold 30 cans of 4-kilos=120 kilos????????????.

'3'  what(s) ?

The answer is "D"  all of the above !      Ha

To  WHAT do you need an answer???

~jc

Hmmm..... Need a picture or diagram to help you with this one....sorry!

~jc

Not sure what ya got goin' there.....can yo clarify that a bit?

IF its a 9 x 9ft    that equals   9 x 9 = 81 sq ft

IF the other one is a 6 x 9  that equals  6 x 9    =   ?    sq ft

OK?

~jc

Sorry...you're not right.....but you're VERY close !

I had to sleep on this last night, but I came up with this answer:

x1 = Amount invested at 3%

x2= Amount invested at $%

etc.

We know Present Value + 100,00 BUT we do NOT know what the Future value will be...BUT we do know they will all be equal....

  x1(1.015)^10 = x2 (1.020)^10 = x3 (1.025)^10  etc     

   SO we need to equate all of the Future Values bact to the Present and express them in terms of x1  Like this

x2 = x1(1.105)^10/(1.020^10)    for all of the terms.....then add them all together , equate them to 100000 and solve for x1   etv

Here is what results (to the PENNY):

x1 (3%)  =22,002.49

x2(4%)  =20,947.42

x3(5%)  =19947.73

x4(6%)  =19000.28

x5(7%)  = 18102.09

It involved a lot of power of ten fractions that had to be calculated.....thanx for calculators with memories!!!!

The final value of each cd will be equa @ 25534.78 for a total of 127673.90

TaDa!    Fun !

~jc 

1.) Last summer, Ben sold lemonade. On a certain day, he observed that the money he had , consisted of 25¢ coins and $5.00 coins. In fact, 9 less than twice the number of 25¢ coins was the number of $5.00 coins. The total value of money is $129.25. How many coins of each type were there?

Let q=number of .25c

Let d=number of $5

2q - 9=d, and,

.25q + 5d=129.25

Solve the following system:
{2 q-9 = d
5 d+0.25 q = 129.25

In the first equation, look to solve for d:
{2 q-9 = d
5 d+0.25 q = 129.25

2 q-9 = d is equivalent to d = 2 q-9:
{d = 2 q-9
5 d+0.25 q = 129.25

Substitute d = 2 q-9 into the second equation:
{d = 2 q-9
0.25 q+5 (2 q-9) = 129.25

0.25 q+5 (2 q-9) = (10 q-45)+0.25 q = 10.25 q-45:
{d = 2 q-9
10.25 q-45 = 129.25

In the second equation, look to solve for q:
{d = 2 q-9
10.25 q-45 = 129.25

10.25 q-45 = (41 q)/4-45 and 129.25 = 517/4:
(41 q)/4-45 = 517/4

Add 45 to both sides:
{d = 2 q-9
(41 q)/4 = 697/4

Multiply both sides by 4/41:
{d = 2 q-9
q = 17

Substitute q = 17 into the first equation:
Answer: |  d=25  and  q=17
 

i got 143, message if im right?

the average of two numbers is 4 1/8. if one number is 5 1/2, what is the other?

Since the average of 2 numbers is 4 1/8, then we have:

2 X 4 1/8=8 1/4, therefore the 2nd number is:

8 1/4 - 5 1/2=2 3/4

Thanks, forgot about factorising it into pairs

Factorise 2y squared + 9y - 5

I've gotten to 2y squared + 10y - y - 5, but don't know how to factorise from there

That is a really good start :)

Next you factorise in pairs

2y(y+5)-1(y+5)

=(2y-1)(y+5)

3) could be 99 $100 and 1 $50 0r 90 $100 and 141 $50

Mon  23/11/15

1) Riddler's riddles.    Geno got one but the other is unanswered. :)   Thanks Geno and Ridler :)

http://web2.0calc.com/questions/riddles-for-ages

2) Fun facts continued  Thanks Riddler

http://web2.0calc.com/questions/fun-facts#r3

3) Problem simultaneous equations with a challenge question added.    Thanks Geno and guest.

http://web2.0calc.com/questions/in-pta-fundraising-activity-couples-who-came-were-charged-400-however-if-only-one-parent-came-he-was-charged-250-00#r3

4) 2 very different answers for a half life question.  Thanks Geno3141 and guest. :D

http://web2.0calc.com/questions/chemistry_8658

5) Logistics problem  Thanks CPhill and jc

http://web2.0calc.com/questions/logistic-model-help-thank-you

6) Singing crickets and modular arithmetic. 

http://web2.0calc.com/questions/math-problem-sum