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 #65
avatar+118723 
+10

!! HAPPY NEW YEAR !!

 

@@ What is Happening?  [Wrap4]   Fri 1/1/16   Sydney,  Australia Time 8:45 pm   ♪ ♫

 

Hi all, 

It is already busier, too bad I like it quiet but that is ok :)  We has some great answers from geno3141, Complex, gibsonj338, Alan, Dragonlance and Bertie.  Thanks all    laugh

 

Technical Issues:

How can you post a picture when the picture upload on the forum is not working properly ?

Thanks very much Alan for these instructions.

http://web2.0calc.com/questions/ven-diagram-need-help-for-questions#r3

 

Interest Posts: 

If you ask or answer an interesting question, you can private message the address to me (with copy and paste) and I will include it.  Of course only members are able to do this.  I quite likely will not see it if you do not show me.

 

1)  Happy New Year

      http://web2.0calc.com/questions/happy-new-year_1

2)  Happy new year from Nauseated

     https://web2.0calc.com/questions/i-need-to-find-the-asymptotes-of-this-hyperbola-x-2-2-121-y-5-2-81-1#r12

3)  Great spacial concepts question:  Not answered on purpose.

     Maybe one of our 13 to 16 years olds might like to try it??   [Thanks Dragonlance laugh ]

     http://web2.0calc.com/questions/sphere_2

4)  Great geometry / algebra question from Mellie.

     https://web2.0calc.com/questions/a-diagonal-of-a-rectangle-has-length-41-and-the-perimeter-is-98-find-the-area-of-the-rectangle

5)  Building a trig graph        Melody

     http://web2.0calc.com/questions/f-t-5-cos-pi-4-t-11

6)  Binary to Decimal    (3 different methods) Thanks Melody, Bertie and guests.

     http://web2.0calc.com/questions/binary-to-decimal

7)  Calculus    Melody and guest

      http://web2.0calc.com/questions/good-evening_1

8)   Fourier Transform       Thanks Alan

      http://web2.0calc.com/questions/serious-question-fourier-transform-makes-no-sense-to-me

 

                                                  ♪ ♫      Melody    ♪ ♫      

Lantern Thread:                          

Jan 1, 2016
 #4
avatar+118723 
+5

I just want to look at these methods, especially Bertie's method   frown

 

11000000111001

 #3 Guest

Better is to use the 'double and add the next digit' method.

Consider an easier example first.

1011 -> 8 + 0 + 2 + 1 = 11

Start with the 1 at the left hand end, double it and add the next digit, 2*1 + 0 = 2, double that and add the next digit, 2*2 + 1 = 5, double that and add the next (the final) digit 5*2 + 1 = 11.

 

Try another one, 110101 (-> 32 + 16 + 0 + 4 + 0 + 1 = 53).

On paper, it's usual to set it out in a column

1     1

1     1*2 + 1 = 3

0     3*2 + 0 = 6

1     6*2 + 1 = 13

0     13*2 + 0 = 26

1     26*2 + 1 = 53.

 laugh

 

If you look in 'Sticky Topics - Great Questions to Learn From', there's a note regarding the conversion of decimal to binary, this is the reverse operation.

-----------------------------------------------------------------------------------------

110101 = 2^5+2^4+2^2+2^0 = 32+16+4+1 = 53

Bertie's Method :  Starting from the LEFT
\(110101_2 \\ = (((((1*2+1)*2+0)*2+1)*2+0)*2+1) \\ = (((( 2^2+2+0)*2+1)*2+0)*2+1)\\ =(((2^3+2^2+1)*2+0)*2+1)\\ =((2^4+2^3+1*2+0)*2+1)\\ =2^5+2^4+2^2+1\\ =32+16+4+1\\ =53\)

 

I learned to do the decimal to binary this way (in reverse).  And I like that method.

I think I learned it from Heureka but it could have been from you.

BUT

This is really weird Bertie, I can see that it works but I think most school students would be better off to make sure that  they understand Our German guests methods.  That is how they would normally be taught at school and it is much more intuitive.  

 

Now I might as well try to do the original question this way:

11000000111001    14 digits  

I am going to use the table tab that is provided for us in the ribbon with 14 rows

1 1
1 1*2+1=3
0 2*3+0=6
0 6*2+0=12
0 12*2+0=24
0 24*2+0=48
0 48*2+0=96
0 96*2+0=192
1 192*2+1=385
1 385*2+1=771
1 771*2+1=1543
0 1542*2+0=3086
0 3084*2+0=6172
1 6168*2+1=12345

 

Ok I got the same as our first guest that is great!

 

NOW i am going to do it MY way - A different way again!

I am going to change it to hexidecimal FIRST

By grouping the digits into 4s starting from the RIGHT     

11   0000   0011   1001 = 3 0 3 9 base 16

\(3*16^3 + 3*16 + 9 = 12288+48+9 = 12345   \)   

If you want me to explain this better then just ask  laugh

 

 

Thanks for showing us your method Bertie  laugh,

I never would have thought to do it like that. :))

Jan 1, 2016
Dec 31, 2015

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