All Answers 358090 Answers

Well Dragonlance it seems you have your life sorted.  You are obviously NEVER bored and never short of something to do.

If you can get time your could go help Colplay's oprimistic brother,

He is shovelling horse poo in an attempt to find the pony :)

If Coldplay is bored, that is what she should be doing.....

That stable, situation reminds me of Sisyphus rolling the boulder up the hill, over and over again for all eternity.

And Sir CPhill seraching for the roman zero that is held withing the boulder...........

Who told Sir Cphill that the zero lay withing the boulder?  I have forgotten.  

I don't know, either......perhaps Alan knows the reason for this.......WolframAlpha will actually give the real solution and the principal root for the non-real solution......

We also can use the Law of Cosines to determine the angles and side orientations.

The angle across from the shortest side =

804^2 = 815^2 + 1145^2  - 2(815)(1145) cos(theta)

cos ( theta) =  [ 804^2 - 815^2 - 1145^2] / [ -2(815) (1145)]

arccos [ 804^2 - 815^2 - 1145^2] / [ -2(815) (1145)]  = theta = about 44.6°

Thus.....the angle across from the second longest side  = 90 - 44.6  = about 45.4°

Thanks Chris :)

You know, I do not really understand why calculators have such a tough time solving problems like this one.

It is not just one calc that has problems, it is almost universal......      

Hi Guest and Dragonlance,

I invite everyone to express their views on this thread.   You are all the inhabitants of this forum. :)

Thanks for that great history lesson Dragonlance.  You must do a lot of homework and have a very good memory to remember all that.

Coldplay likes to troll through old posts too.  :D

You are right though, this forum is The Kingdom of Camelot and like any other city, all types live here and mostly that makes this place interesting and enjoyable. 

You have made me nostalgic Dragonlance,  I would like the Kingdom of Camelot returned to its former glory.  I miss the old characters that are rarely seen these days, like Chiurgeon Morgan Tud, Sisyphus and Morgan De Fay.   

Our guest is also partly right.  Like with all growing cities, laws and attitudes must be moulded to meet the ever changing needs of the population.

Guest I would like to hear your views on how Camelot should change.  

Not so much what you think Mr Massow shoud do, like Dragonlance said, he is the King and he will do it as he pleases.

BUT,  

How do you think that the moderators should behave differently.

What you like us to do differently.

I invite everyone to join this thread - that is if you have anything interesting of helpful to say.   :)

Thanks, Melody.......cool graph, too !!!

If the survey indicates the general trend.....then 75% of the students got 8 or more hours of sleep per night....so....

75% x 4900  =

.75 x 4900  =

3675  students got 8 or more hours of sleep

Why is -5 the answer of the cube root of negative 125 when the answer to the equivalent equation negative 125 to the power of 1/3 is not a real number?

All cube roots have 3 answers.

The calculator only looking for real roots only looks on the positive x axis.

No cubic root of -125 is on the positive x axis so a no real roots answer is returned.  Some things calculators do not do very well.  We have to interpret and understand the answers.

Here are the 3 roots of -125 displayed on a complex number plan.

I thought that you might find it interesting :)

Asked again here

You already asked this question here

It depends

write 9:50 as a percent

If you want the first as a percenage of the second than it is certainly 18%

BUT

If you want the first as a percentage of the whole it is   9/59*100% = approx  15.25%

Hi Solveit,

I do not understand, couldn't you delete the picture when you realized it was the wrong one?

I am not upset with you, I a m just trying to ascertain if there is something about the site that I don't understand.

I was only just told last night that normal members cannot edit their posts for very long after they are  posted.

I didn't know that......

Oh, I see,  that is what you were trying to tell us in your first answer post.  Ok   

Side lengths of a right angle triangle are 1145, 804 and 815. What size are the other two angles.

Sin(815/1145)=0.711790 [This is an assumption, since we do not know which side is the Adjacent side and which side is the Opposite.]

Asin(.711790)=45.38 degrees-one of the other two angles.

180 - [90 + 45.38]=44.62 degrees-the third angle.

Thanks Girls.

I am sorry Hayley but Coldplay wins the joke telling competition!    

I am the only one who gave you any points but I like the pony one :))

See you Tuesday DS :)

I just want to rewrite your question.....

Set  

\(a=6 - 4\sqrt{2}, \qquad   y=\sqrt2 - 1, \qquad  n=0, 1, 2, 3.........etc.   \)

 Iterate the following..........

\(y=\frac{1 - (1 - y^4)^{1/4}}{ 1 - (1 + y^4)^{1/4}}\)

then:

\(a=a(1 + y)^4 - [2^{(2n+3)}* y(1 + y +y^2)]\)

..........converges to what?.

The number of grains on the 28th square is: 2^(28-1)=2^27

Total number of grains on all 28 squares is: (2^28) - 1

I don't understand the question......

it =sqrt(120 over 11

y-1y =0

ok ? 

thanks for that

Simplify the following:
sqrt(120/121)

sqrt(120/121)  =  (sqrt(120))/(sqrt(121)):
(sqrt(120))/(sqrt(121))

sqrt(121)  =  sqrt(11^2)  =  11:
(sqrt(120))/(11)

sqrt(120)  =  sqrt(2^3×15)  =  2 sqrt(2) sqrt(15):
(2 sqrt(2) sqrt(15))/(11)

sqrt(2) sqrt(15) = sqrt(2×15):
(2 sqrt(2×15))/(11)

2×15  =  30:
Answer: | (2sqrt(30 ) ) / (11)

You can do fractions on it, but I find this online dedicated fractions calculator much easier to use:

http://www.calculatorsoup.com/calculators/math/fractions.php