So ...first lets see the outcomes....they are
1 , 2 , 4, 5, 1 ,2 ,4 ,5 ,6
now look at the outcomes.....we need to find the probablity of getting " 1" ....look at the outcomes again....and count how many times " 1 " is occuring....
so 1 is occuring 2 times....so this is how we solve it
Total Outcomes = 9
Favourable Outcomes = 2 (which means that 1 is occuring two times and that is what we need)
P(E) = F.O. / T.O.
P(E) = 2/9
so if we could be able to solve this more...we would but since they are unsolvable...we wont...
so thats your answer!
hope you learnt something!
