All Answers 358087 Answers

If you are looking at the TOTAL rolls as an outcome, there are  6 x 6 x 6 x 6 x 6 x 6   possible outcomes    6^6 = 46656 possibilities

Use pythag theorem

9^2 + h^2 = 15^2

h= 12ft

(1/2)^20/10  =( 1/2)^2  = 1/4

i believe they're are 6 different outcomes,1,2,3,4,5,6

well 3% is equal to 0.03 but what do you want to add 3% to?

why is what 0.7 i mean 70% is equal to 0.7 but i don't know what you are talking about

ummmmmm i am pretty sure that it is a-zero,because everyone says that the people on their left and right are liars so that means that evaryone in the group is a liar.

Polar form is ( r, θ)

r = sqrt  [ (2√3)^2 + (-2)^2 ]   = sqrt [ 12 + 4]   = 4

arctan [ -2/ (2√3) ]  =  arctan [ -1 / √3  ] = θ =  330°

So, polar form  is  ( 4, 330° )

BTW....this answer is not unique.....there are infinite possibilities.......

You can use the Quadratic Formula as previously illustrated.    You can also 'complete the square'

Take 1/2 of the 'x' coefficient, square itn and add it to both sides:

x^2 -4x + (-2^2) = 11 + (-2^2)

x^2 -4x +4 = 15

(x-2)^2 = 15         Now take the sqrt of both sides

x-2 = +- sqrt15

x = 2 + or - sqrt15        (same answers as Quadratic Formula)

OML TYSM

First you have to be careful about the different changes in measurement here.

To be on the safe side i converted everything to grams.

So:

1080 grams of fertiliser.

0.097*3=0.291

1080/0.291=3711.34...

So he can fertilise 3711 plants

180-x=10+2(90-x)     simplify

180 - x = 10 + 180 - 2x

180 - x   = 190 - 2x     add 2x to both sides, subtract 180 from both sides

x = 10

1.08 kg   is 1080 gm = 1,080,000 mg

each plant gets 97mg x 3  each year = 291mg

1080000/291 = 3711.34   or   3711 plants    He will have enough fertilizer left over for .34 plants      .34 x (291) =  98.94 mg left over

Impressive!!!

x^2 + y^2  - 4y   =  0  

[r cos θ]^2  + [ r sin θ]^2 -  4[r sin θ] = 0

r^2 [ sin^2 θ  + cos^2 θ]   - 4r sin θ  = 0        [ remember  sin^2 θ  + cos^2 θ = 1]

r^2  - 4r sin θ  =  0    divide through by r

r  - 4sin θ  = 0     add 4 sin θ  to both sides

r = 4 sin θ

x^2-4x=11

First you take away the 11 so you have a quadratic.

x^2-4x-11=0

Now you factorise.

Since 11 is a prime number we shall have to use the quadratic equation:

a=1

b=-4

c=-11

Your two possible solutions are:

x=5.87....

or 

x=-1.87....

Thank you!  

https://www.mathsisfun.com/algebra/factoring-quadratics.html

x^2+10x=-21

Step 1: Add 21 to both sides to make the equation equal to 0

x^2+10x+21= 0

Step 2 : Use Factoring to find the zeroes of the equation

(x+3)(x+7) = Factored Answer

Step 3: Make each part equal to =zero to find the zeroes

x+3= 0        x+7= 0

x=-3             x= -7

x^2+10x=-21

get all on one side

x^2+10x+21=0

factor-what plus what =10

           these two numbers also must multiply to 21

7+3=10

7*3=21

(x+7)(x+3)=0

x+7=0 or x+3=0

x=-7 or x=-3

x coordinate =  6cos(240°)  =  6(-1/2)  = -3

y coordinate  =  6sin(240°)  = 6( -√3  / 2 )    =  - 3√3

x^2+6x=16

x^2+6x-16=0

(x+8)(x-2)=0

(x+8)=0 or (x-2)=0

x=-8      or   x=2

x=-8 or x=2

tnx bro

240/280 = 0.8571428571428571

*100

=85.71

so the answer is A