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For standard arithmetic it doesn't!  To see under what conditions it does, watch the following:  https://www.youtube.com/watch?list=PLmNp3NTX4KXIqtjt2AKOr4DUIxn64xj8G&v=jcKRGpMiVTw 

\(\frac{3x}{3x}+64.100=72.4\)

\(\frac{3x}{3x}+64.100≠72.4\)

\(\frac{3x}{3x}+64.1≠72.4\)

\(1+64.1≠72.4\)

\(65.1≠72.4\)

\(\frac{100}{2}+\frac{\frac{10}{3}}{4}-5\)

\(50+\frac{\frac{10}{3}}{4}-5\)

\(50+\frac{10}{3}\times\frac{1}{4}-5\)

\(50+\frac{10}{12}-5\)

\(50+\frac{5}{6}-5\)

\(\frac{300}{6}+\frac{5}{6}-5\)

\(\frac{305}{6}-5\)

\(\frac{305}{6}-\frac{30}{6}\)

\(\frac{275}{6}\)

\(45\frac{5}{6}\)

\(45.8333333333333333...\)

hello

What expression?

\(-2+15\)

\(13\)

\(-4-\frac{2}{3}-5\)

\(-\frac{12}{3}-\frac{2}{3}-\frac{15}{3}\)

\(-\frac{14}{3}-\frac{15}{3}\)

\(-\frac{29}{3}\)

\(-9\frac{2}{3}\)

\(-9.6666666666666666...\)

\($23,400.00\times0.2\)

\($4680.000\)

\($4,680.00\)

"x" can be ANYTHING because   3x / 3x = just '1'....so your equation is mis-written....can you re ask your question?

Go online to this link and see if it will help you:

http://www.webqc.org/balance.php?reaction=Ag(s)+%2B+H2S(g)+%2B+O2+%3D+Ag2S(s)(tarnish)+%2B+H2O(l)

Possible derivation:
d/dy(1.5-4 y-2 y^2+cos((pi t)/12))
Differentiate the sum term by term and factor out constants:
  =  d/dy(1.5)-4 (d/dy(y))-2 (d/dy(y^2))+d/dy(cos((pi t)/12))
The derivative of 1.5 is zero:
  =  -4 (d/dy(y))-2 (d/dy(y^2))+d/dy(cos((pi t)/12))+0
Simplify the expression:
  =  -4 (d/dy(y))-2 (d/dy(y^2))+d/dy(cos((pi t)/12))
The derivative of y is 1:
  =  -2 (d/dy(y^2))+d/dy(cos((pi t)/12))-1 4
Use the power rule, d/dy(y^n) = n y^(n-1), where n = 2: d/dy(y^2) = 2 y:
  =  -4+d/dy(cos((pi t)/12))-2 2 y
Simplify the expression:
  =  -4-4 y+d/dy(cos((pi t)/12))
The derivative of cos((pi t)/12) is zero:
  =  -4-4 y+0
Simplify the expression:
Answer: |  =  -4-4y

log₉ 40

Using the change  of base rule....this evaluates to

log 40 / log  9   = about  1.679

Area of label on first soup  can =

2pi (d/2) * h  =  

2pi (4/2) * 8  = 

32 pi  inches^2

Area of label on second soup can =

2pi (d/2) * h =

2pi (8/2) * 4  =

32 pi inches^2

They both have the same area!!!

The volume of the two hemispheres  = the volume of one sphere with the same radius =

(4/3)pi(r)^3   =

(4/3)pi (3ft) ^3  =

36pi ft^3

The volume of the cylinder separating them =

pi * r^2 * h  =

pi *(3ft)^2 * (13 ft)  =

117 ft^3

So.....the total volume =

pi [ 36 + 117] ft^3  =

pi [ 153]  ft^3  =    about 480.66 ft^3

AR = QR = RS  = (1/2) QS  = 3

So ....by the Pythagorean Theorem, AS = AQ  =

√ [3^2  + 3^2]   =  √[9 + 9 ]  = √18 

And the area of the two  semi-circles= the area of a circle with a radius of AS/2 = 

pi [AS/2]^2 =

pi [√18/2]^2  =  18pi/4  =  (9/2)pi  units^2

And the area of the rest of the figure is just that of a rhombus  =

The product of the diagonals / 2   =

AB*QS/2  = 9 * 6 / 2  = 27 units^2

So....the total area  =

 [(9/2) pi + 27]   units^2   =  about  =  41.1 units^2  [rounded]

5/11   can never be expressed as a "whole number"  because it's not a "whole number"

                                                                                      __

As the guest said.....the decimal  representation  =  0 .45

Let the area of the semi-circle = (1/2) pi*r^2      where r is the radius

Let the height of the semi-circle = r

Let the perimeter of the semi-circle = pi*r

Let the width of the rectangular part of the window  = 2r

The the length of one side of the rectangle =  [ P - pi*r - 2r] / 2    where P is the perimeter

The.....the total area, A    =

A = (1/2)pi *r^2 + 2r * [ P - pi*r - 2r] / 2 

A =  (1/2) pi*r^2 + r  [ P - pi*r - 2r] 

A  = (1/2)pi*r^2 + Pr - pi*r^2 - 2r^2

Take the derivative

A'  = pi*r  + P  - 2pi*r  - 4r

A'  = P - r [ 4 + pi]

Set the derivative = 0

P - r [4 + pi]  = 0

P  = r [ 4 + pi ]

Solve for r

r  = P / [ 4 + pi ]

So......the ratio of the width of the rectangular part of the window to the total height  =

2r / [ r  + [ P - pi*r - 2r] / 2 ]  =

2r /  [ 2r + P - pi*r - 2r] / 2  =

4r / [ P - pi*r ]

Substitute  P / [ 4 + pi ]  for r

(4 P / [ 4 + pi ] )  / (  P - pi *P / [ 4 + pi] )

(4P)  / ( 4P + pi*P - pi*P)  =

(4P) / (4P) =

1 / 1

So.....the width of the window = the total height of the window to maximize the area for any given perimeter

Well, it is a fraction: 5/11=.45454545.............You can multiply it by 11, so that you get: 5/11 x 11=55/11=5

1 / 1+(0.28/4)^4

1/ 1.07^4

1/ 1.31079601=0.762895212. I believe your 0.28/4 should be:0.028/4. Check it carefully.

how do I calculate (2.5)^(0.5)-1

Sqrt(2.5) - 1 =0.5811 x 100 =58.11%

Your IRR shoudn't be this high!. You should state you problem in full and will show you how to calculate IRR.

"!"  means  "factorial"

0!  =  1

1!  =  1

2!  =  2x1  =  2

3!  =  3x2x1  =  6

4!  =  4x3x2x1  =  24

5!  =  5x4x3x2x1  =  120

The fact that  0! = 1  might seem strange, but it's necessary for some formulas.

If  n > 1,  then  n!  =  n·(n - 1)·(n - 2)·(n - )·...·3·2·1

y  =  2^x