All Answers 358514 Answers

$${{\mathtt{5}}}^{{\mathtt{7}}} = {\mathtt{78\,125}}$$

lol WHY CPhill that didnt solve anything

first you need to subtract 16, or add negitive 16 to each side

then, just take the square root of -26, and you have x!

OK......but consider this......

I'll give you (2 + 2) dollars every day for a year

And you can give me 5 dollars every day for a year

And since we claim that 2 + 2 = 5

We should both be happy

lol thumbs up on that LOL ill remember that everyday

Right idea.....but wrong execution.....

x < 512

Whatever "x" is, it's less than 512......

Simpify what ???

You could do it by hand.....but it gets pretty tedious, sometimes....(almost impossible, at others)

The on-site calculator will handle this operation just fine....try it !!!

Add 16 to both sides

x^2 = 3    Take the square root of both sides....remember, we need to take both roots - positive and negative

x =  ±√(3)

And that's it.......

It looks like you want to find a missing dimension, but I can't tell from your question which one you're missing.

I'll let "x" represent the missing dimension and you can plug it in where you need to.....

3 * 4 * x = 144

12 * x = 144        Divide by 12 on each side

x = 12

$$X^2-16=-13
Add 16
X^2=3
Square root it and you estimate$$

I learned another little "trick' to remember them...

Sin  = Oh Heck !!

Cos = Another Hour

Tan = Of Algebra !!

192 = -16t²+48t+160 Subtract 192 from both sides

0 = -16t²+48t-32  Multiply through by -1

0 = 16t^2-48t+32  Divide through by 16

0 = t²-3t+2  Factor

0 = (t-1)*(t-2)

So there are two solutions:  t = 1 and t = 2

Chris beat me to it!

192 = -16 t^2 + 48t + 160

Let's move everything over to the left side......we get

16t^2 - 48t + 32 = 0     Factoring out the "16," we have

16 (t^2 - 3t + 2) = 0     Dividing by 16 on both sides

(t^2 - 3t + 2) = 0          Factoring, we get

(t -2) (t -1) = 0              And setting each factor to 0, we have

t = 2  and t = 1

speed = distance/time

Adam's speed = L/4.92   if L is the distance.

Anthony's speed = L/6.3

Adam's speed/Anthony's speed = (L/4.92)/(L/6.3) = (L/4.92)*(6.3/L) = 6.3/4.92

$${\frac{{\mathtt{6.3}}}{{\mathtt{4.92}}}} = {\frac{{\mathtt{105}}}{{\mathtt{82}}}} = {\mathtt{1.280\: \!487\: \!804\: \!878\: \!048\: \!8}}$$

so Adam is approximately 1.28 times as fast as Anthony, or about 28% faster.

Let me see how much of this I remember.......!!

The first one is  A ∩ (B U C), which, by Distributive Laws can be writtten as:

(A ∩ B) U (A ∩ C) =

({a, b, d} ∩ {b, d, e, f }) U { } =

{b, d } U { } =

{b, d}    {By, defnition, the empty set is a subset of every set}

The second one is (B’ ∩ C)’ - A  ...   which, by using De Morgan's Laws  can be written as

(B U C') - A =

({b, d, e, f} U {a, b, d, e })  - {a, b, d } =

({a, b, d, e, f} - {a, b, d}) = {e, f }

I believe that's it........but if someone else can check my answer , it would be great !!

yeah sure but not like theres a friend request system lol

It just is the distance a number is from zero on a number line.

$$Area=\pi rl+\pi r^2$$

$$\\
\frac{Area2}{Area1}=\frac{4r\frac{l}{6}+16r^2}{rl+r^2}\\\\
Area2 = Area1*\frac{2(l+24r)}{3(l+r)}$$

Oh, by the way, you're welcome.

I like it when people thank other people, so you wanna be friends? (Possibly...?)

Thank you Alan, these are the results I came up with as well and they match. Thanks for making it clear.

THX SOOOOOOOOOOO MUCH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

6.3-4.92=1.42 minutes.