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More symbols here  :))   Thanks Max

http://web2.0calc.com/questions/off-topic-just-trying-to-make-a-picture

There are many really helpful symbols here

Thanks Max :)

ok that is a double dagger :))

btw that's \ddagger not \dagger

All except \infty from http://omega.albany.edu:8008/Symbols.html

I discovered \infty myself.

Thanks Max,  That S one is quite interesting.  Where are your referencing these symbols from?

\dagger            \(\dagger\)

\S                    \(\S\)

\infty               \(\infty\)

\cdot \space \cdot \\ \smile           \(\cdot \space \cdot \\ \smile\)

\cdot \space \cdot \\ \frown        \(\cdot \space \cdot \\ \frown\)

Depends what is meant by a "complete" graph, I guess:

Do the brackets first.

8 = 6x + 42 + x

Then combine like terms

8 = 7x+42

Move the 42 to the other side of the equal sign,

7x = 8 - 42 = -34

x = \(\color{blue }-\dfrac{34}{7}\)

No one can see your question so I can't help you. Joking. Just highlight it.

Using the sine rule, \(\color{blue}\dfrac{a}{sin48}=\dfrac{5}{sin26} \\ \color{blue}a=\frac{5sin48}{sin26} \approx 8.47\)

\(\S\)

\(\S \infty \S\)

\(\S\infty\infty\infty\S\)

\(\S\infty\S\)

\(\S\)

Thanks Chris,

It is impossible to answer this question - there simply is not enough information to base an answer on :)

Yes Max, I get your answer too. :)

Your answer is good Max but answers only do not help people learn.

Your better of to give a half answer with no final answer than a final answer with no working.

In fact I think half answers are often really good. :)

Slope is -2/5      I don't know the y intercept but the line passes through ( -2,2)

\(y=mx+b\\ y=\frac{-2}{5}x+b\\ Sub\;\;in\;\; x=-2 \;\;and\;\; y=2\\ 2=\frac{-2}{5}\times -2+b\\ 2=\frac{4}{5}+b\\ 10=4+5b\\ 6=5b\\ b=\frac{6}{5}\\ so\\ y=\frac{-2x}{5}+\frac{6}{5}\\\)

Here it is in the LaTex thread :))

Thanks to MaxWong                                 Cards Suites  

A card is drawn at random from a pack of 52 playing cards(\(\clubsuit \diamondsuit \heartsuit \spadesuit\))

(without Jokers). What is the probability of getting a card which is neither a 6 nor a ?

\clubsuit \diamondsuit \heartsuit \spadesuit

Thanks Solveit

That is a good answer - I'd be inclined to keep your answer exact though.  

36/52 = 9/13

Thanks to you too Max, I have not seen the card suits pictured in LaTex before - I will put that in the LaTex thread that we keep with the sticky topics :))

i think:

minus all the cards with heart on it:

52*(3/4)=39

minus all the cards with 6:

39-3=36 (3 because we already have minused one 6 with heart on it)

The probability: 36/52 = 0.6923076923076923(70%)

\(\color{aqua}sec^2\theta + csc^2\theta=\color{aqua}\frac{1}{cos^2\theta}+\frac{1}{sin^2\theta}=\frac{sin^2\theta+cos^2\theta}{sin^2\theta cos^2\theta}= \frac{1}{sin^2\theta cos^2\theta}\space OR\space sec^2\theta csc^2\theta\)

(Same as CPhill's answer, just using LaTeX to make it clearer.)

:D

\(\frac{1.0\times10^{-14}}{7.92\times 10^5}\)

\(=\frac{1}{7.92}\times \frac{1}{10^{19}}\approx 0.1262626\times 10^{-19}\)

32 = 7-5y

y = \(\frac{7-32}{5}=-5\)

I can't comprehend this question. Please present the question in a better way.

log 53

0| 1 1 1 2 2 2 4 8 8

1| 9

2| 3 6 7 

\(f(x)=\frac{3}{x}+2-\sqrt{x}-2\)

\(f(7)=\frac{3}{7}-\sqrt7\approx-2.22\)

32) \(3\sqrt[3]{5y^3}\times2\sqrt[3]{50y^4}\)

= \(3y \sqrt[3]{5}\times 2\sqrt[3]{5\times5\times2\times y^3\times y}\)

= \(6y\sqrt[3]{5}\times y \sqrt{50y}\)

= \(6y^2 \sqrt[3]{250y}\)

= \(6y^2 \sqrt[3]{5^3\times 2y}\)

= \(6y^2\times 5 \sqrt[3]{2y}\)

= \(30y^2\sqrt[3]{2y}\)

\(6^3 \times 6^{-2}= \frac{6^3}{6^2}= 6\)

Oops sorry wrong answer :( Had to do it all over again.

Just realized angle AEB = angle DEB = 90 degrees.

BD = \(\sqrt{3^2 + \sqrt{11}^2} = \sqrt{20}\)

BC = \(\frac{5\sqrt{2}}{2}=\frac{5}{\sqrt{2}}\)

BC² = \(\frac{25}{2}\)

X = 25+2 = 27

For Y, I admit that I am wrong and it should be a fruit which is cashew apple which makes 1 + 16 + 16 + 12 + 5 = 50

Now testing numbers between 275011 and 275098

Why 275011 and 275098? It is because the digits can't repeat and 275000 to 275010 and 275099 does not satisfy the conditions.

No such numbers satisfys such conditions.

Lesson taught: Don't even try that lock and quickly get back to water surface