All Answers 356017 Answers

The answer to 2+2 is 4

22 people

given f(x)= 5x+4/5x^2+4x and g(x) = 1/x

simplify f(x) and find any vertical asymptotes

-6x+2=3(-2x+1)

-6x+1/(-2x+1)=3(-2x+1)/(-2x+1)

3x/1x=3

x=1

There are several ways to do this, but here's one.  Assuming that, at t = 0, height = 29 ft, we have :

h(t)  =  29 + 25sin [(pi/6) * t ]

Here's a positional graph : https://www.desmos.com/calculator/uwjipvodqu

BIČ IZ 3 OK?

Back in 1820, the Illuminati needed a means of communication which was uninterpretable by beings of lesser intellignece, so they created modern math.

Light travels 186,282 miles per second

1 mile=5,280 feet

186,282 x 5,280 =983,568,960 feet per second-speed of light

1 nanosecond =10^-9 of 1 second

983,568,960 x 10^-9 =0.98 feet in 1 nanosecond=11.8 inches in 1 nanosecond.

(x^3-a^3):(x-a)  =

[ (x - a) (x^2 + xa  + a^2)] /  (x - a)  =

(x^2 + xa + a^2)

cos 2x - sin x = 0      note:  cos 2x =  1 - 2sin^2x

1 - 2sin^2x - sinx    =   0      multiply through by -1

2sin^2x  + sin x   - 1   = 0     factor

(2sinx - 1) (sinx + 1)  =  0      set each factor to 0

2sinx  - 1  = 0    add 1 to both sides

2sinx  = 1      divide both sides by  2

sinx   = 1/2       and this happens at   pi/6  and 5pi/6   on the requested interval

And

sin x + 1 = 0    subtract 1 from both sides

sin x = -1       this happens at 3pi/2, which is outside the requested interval

i am back

5 x 12= 60

1/2 x 12= 6

60+6=66

If you can get the quation into the form  y = mx + b     m is the slope

y-5 = -2(x+5)

y = 5  - 2x - 10

y = -2x - 5            m= slope = -2

The amount whose name trillion km where No. 5

-6x + 2  =  3(-2x + 1)

-6x + 2  =  3(-2x) + 3(1)

-6x + 2  =  -6x + 3

Add 6x to both sides:

         2  =  3

This is impossible; therefore, there is no possible solution to this problem.

Write these into exponential notation and check ...

    log_bN = x     in exponential notation is    b^x = N

In common logs, the base is 10 but it usually isn't written. I am going to write it so it is clear.

log₁₀(10³) = 3         written in exponential notation is  10³ = 10³               Is this true?

log₁₀(1/10) = 0,1    written in exponential notation is  10^0,1  =  1/10          Is this true?

10^log₁₀7 = log₁₀7     written in exponential notation is  10^log₁₀7 = log₁₀7     Is this true?

log₁₀(1/10)³ = -1/3  written in exponential notation is  10^-1/3 = (1/10)³       Is this true?

Write each of the problems into exponential notation and check ...

Rule:     log_bN = x    in exponential notation is     b^x = N

log₂16 = 8  in exponential notation is  2⁸ = 16     Is this true?

log₄2 = 1/2  in exponential notation is  4^1/2 = 2     Is this true?

2log₂47 = 47  can be written as  log₂47² = 47  in exponential notation is  2⁴⁷ = 47²     Is this true?

log₃9 + log₃(1/27)  =  1/2  can be written as  log₃(9·1/27)  =  1/2  which is  log₃(1/3) = 1/2

                                       in exponential notation is  3^1/2 = 1/3     Is this true?

288

log(base 2)16=8 true or false?

log(base 4)2=1/2 true or false?

2log(base 2)^47=47 true or false?

log(base 3)9 + log(base3)1/27=1/2 true or false?  

help

Hello Deathrises!

What is -1(-2)(-3)(-3) ?

(-1)(-2)(-3)(-3) = (-1)⁴ * (1 * 2 * 3 * 3) = + 18

Gruß asinus :- )  !

Hello Guest!

What is 40/17 in fraction form ?

Clicking the link ∑LaTeX above.\(\)

Delete in case "x = {-b \pm \sqrt{b^2-4ac} \over 2a}"

Write in the box    40/17= \frac{40}{17}   Give OK

It appears \(\) \( 40/17= \frac{40}{17} \)

Greeting

asinus :- )

  !

-1(-2)(-3)(-3)

Since -1·-2  =  2:                        (a negative times a negative is a positive)

=  2(-3)(-3)

Since 2·-3  =  -6:                        (a positive times a negative is a negative)

=  -6(-3)

Since -6·-3  =  18

=  18