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what is 5 and 2\3 divided by 1\6

Hi cassdy1,

To start with your fraction lines are the wrong way around.  They have to be like /

now

$$5\frac{2}{3} \div \frac{1}{6}$$

first you have to change the mixed numeral into an improper fraction.   3*5+2=17 that goes on the top and 3 goes on the bottom

$$=\frac{17}{3} \div \frac{1}{6}$$

Next, when you divide by a fraction you invert (the second one ) and multiply

$$=\frac{17}{3} \times \frac{6}{1}$$

$$=\frac{17\times 6}{3\times 1}$$

Now, 3 goes into itself 1 time and into 6 two times

$$=\frac{17\times 2}{1\times 1}$$

$$=\frac{34}{1}$$

34 divided by 1 is 34

=34

Let's convwert 5 + 2/3 to a fraction = 17/3

So we have

17/3 / 1/6         The rule is to "keep" the first fraction, "change" to multiplication  and "flip' the second fraction......So we have

17/3 x 6/1      We can "cancel" the 6 and the 3 and get 2    So we have

17/1 x 2/1  = 34

Remeber when we divide fractions......"keep"  "change" "flip'"

Okay so we have $$\frac{5\frac{2}{3}}{\frac{1}{6}}$$

Let's first rewrite $$5\frac{2}{3}$$ into one fraction.

$$5\frac{2}{3} = \frac{17}{3}$$

Then we make it 6'th instead of 3'rds

$$\frac{17}{3} = \frac{34}{6}$$

Okay, so now we have $$\frac{\frac{34}{6}}{\frac{1}{6}}$$ Since they are both 6'th I can rewrite this to

$$\frac{34}{1} = 34$$

If you find this difficult to see you can also do this; rewrite $$5\frac{2}{3}$$ to $$\frac{17}{3}$$

Then $$\frac{\frac{17}{3}}{\frac{1}{6}} = \frac{17}{3}*\frac{1}{\frac{1}{6}}= \frac{17}{3}*6 = 17*\frac{1}{3}*6 = 17*\frac{6}{3} = 17*2 = 34$$

Reinout 

14c - 21 

Set the problem equal to zero   14c - 21 = 0

Add 21 to both sides  14c = 21

Divide both sides by 14  c = 1.5 or 1 1/2

Do you mean 14c = 21 ??   If so, we have

Divide both sides by 14   We have

c = 21/14  = 3/2

If you mean you'd like to factor this, we have

7 (2c - 3)

I don't know if that helps, or not!!

I can interpret this in multiple ways but all have an invalid answer.

I'm going to interpret it as

  $$y = ^4log(1.5*1.3*0.5*0.75-1)$$

which is the log {base4} of (1.5*1.3*0.5*0.75-1) 

(and y is your answer)

We can rewrite this to $$4^y = 1.5*1.3*0.5*0.75-1$$

Now since $$1.5*1.3*0.5*0.75-1 \leq 0$$ and $$4^y \geq 0$$ for any y

There exist no y for which this equality holds.

Therefore you equation has no answer.

Instead of base 4 I can interpret it as base 10 or a natural logarithm but it still won't give me an answer.

Perhaps you want to check whether you wrote down the question correctly 

Reinout

I'm not quite sure what you mean.

$${\mathtt{1.5}}{\mathtt{\,\times\,}}{\mathtt{1.3}}{\mathtt{\,\times\,}}{\mathtt{0.5}}{\mathtt{\,\times\,}}{\mathtt{0.75}}{\mathtt{\,-\,}}{\mathtt{1}} = {\mathtt{\,-\,}}{\frac{{\mathtt{43}}}{{\mathtt{160}}}} = -{\mathtt{0.268\: \!75}}$$

And you cannot find the log of a negative number - they don't exist.

x-3x  

what is 7X-2X?  7crosses -2crosses = (7-2)crosses = 5 crosses = 5x

x-3x = 1cross - 3 crosses = (1-3)crosses = ??? Do you know what 1-3 is?

It is a big number so the power will be positive.

There has to be just one non zero number in front of the point - that will be the 7

So it will be 7.5 x 10 to the +something

At the moment there is an invisable  decimal point at the very end.  You have to jump it over all the digits until you get it between 7 and 5.  It will have to jump over 6 digits.  

So the answer is

7.5 x 10⁶

Give me an example, I'll explain while I work it out for you 

For not fore

Depends on what volume you're calculating.

The most basic form is the box which has the formula volume = base*width*height

But there are several other too such as;

Cube - side^3

Sphere - (4/3)*pi*radius^3

Cylinder - pi*radius^2*height

etc.

Well done anonymous!

I think something messed up your table a little but your answer is still correct.

Do you have a registered account, so I can see who's the genius behind the answer?

If you don't please do... It takes little time and makes us able to identify you on the forum. 

Reinout

This is simply a rounding error for the factorial calculation (N!)

The rounding error precision for the factorial function is readily apparent after recent revisions, but has occurred in other previous revisions.

Currently, the calculation is 17 digits with an error of -1 to +1 in the 17 digit. The ncr and npr do not appear to be affected by this error.

When the product is obtained by multiplication, or exponent function(x^y) its precision is usually accurate to over 200 digits and up to 300 digits for certain bases and exponent values.

Calculation precision errors in Log, Trig, and other related functions are demonstrable. Subtle errors appear as apparent pseudo-random numbers occupying the last digits or decimal places in the resolved function outputs.

For Log and anti-Log functions, the errors have occurred for over 5 years.

This computer generated “calculator” is a brilliant peace of programming. At one time, this calculator would generate results with atomic accuracy at galactic distances (plus or minus the bugs and limitations of log and trig functions). Now, most functions (except for exponential) are rounded to 16 or 17 digits. This is more like galactic accuracy at atomic distances, but it keeps the FLOP load down when tens of thousands of users are seeking solutions.

~~D~~

think of pos numbers  as hot  and neg numbers  as cold.

If i add 10degrees of cold it must get colder so 0+-10=0-10=-10

negative 10

sin(x)=3/100

When you are looking for the angle you must use inverse sin or arc sine (they are the same thing)

x=asin(3/100)

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{3}}}{{\mathtt{100}}}}\right)} = {\mathtt{1.719\: \!131\: \!320\: \!878^{\circ}}}$$