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I made it like that on purpose. Get recttttt

You spelled Piperson’s name wrong.

n-4(1+5n) =-2    simplify the left side

n - 4 - 20n  = -2

-19n - 4   = -2     add 4 to both sides

-19n  = 2         divide both sides by -19

n = -2/19

Hi Miss Rosala,

Of course, we want your post(s). Sometimes your audience may be small, but we are loyal as puppies (and chimps).

 P.S.  Re-visit your birthday post. More have added their greetings. 

GA

Your funny posts are always good, rosala..........post it !!!!

Maybe this will help  :   http://www.purplemath.com/modules/solvpoly2.htm

3x - 13 = 7(x + 2) -4 (x -7)     simplify the right side

3x - 13 =  7x + 14 - 4x + 28

3x + 13 =  3x + 42    this has no solution........we can't add two different quantities to 3x and expect the same result!!!!

-|8x+2| >-10        multiply throgh by -1 and change the direction of the inequality sign

 l8x + 2l  < 10      we have two equations here

Let's make this an equality and then we can figure out what the proper solution interval(s) might be

8x + 2 = 10                           and    8x + 2 = -10

subtract 2 from both sides

8x = 8                                     8x = -12 

divide both sides by 8

x = 1                                  x = - 12/8  →   x = - 3/2

Note that the proper solution interval will lie between these two values.....thus

-3/2 < x < 1

The graph here indicates that this solution is correct :

https://www.desmos.com/calculator/ah5tytaeku

Like this: [12 x 11 x 10 x 9........x 1] / [2 x 1 x 10 x 9 x 8 x 7.......x 1] =66

Right Piperton! Melody is going to solve a million-dollar math problem for someone too lazy or stupid to present it properly.  What you have is worse than CDD.  You have Contagious Don’t Give a Dámn Disease (CDGDD). 

This is the “Beal Conjecture”

IF

\(A^{x}+B^{y}=C^{z}, \)

\(\text { where A, B, C, x, y, and z are positive integers with x, y, z > 2,}\\ \text { then A, B, and C have a common prime factor. } \)

GA

3 😂

90/100 x 400 = 360

When the vehicle stops, it's velocity will be 0    vf = 0

Use   vf = vo + a t    to calculate 't'       vo = original velocity 50 m/s   a = -12 m/s^2

then use the 't' in

xf = xo + vot + 1/2 a t^2    to find xf= distance to stop   xo = 0 in this instance

You'll need more info.  You will need THREE equations with the three variables to arrive at unique solutions.

Watch this mathematician in this video explain the problem and why you should "switch":

https://www.youtube.com/watch?v=4Lb-6rxZxx0

Just copy and paste in the address bar of your Browser.

I will assume these are times and both are AM on the same day

4:24 to 9:24    is   5 hours 0 minutes difference

Use the starting point and midpoint to calculate the slope and the distance, then extend the distance twice as far.    If you give your specific example we can help you....

Without more info than what you have given, there are infinite 'solutions'.

Solve for r

1. 3(6r - 5) + 2r = 3(r - 5) - 5r, r=0

Solve for b

2. -8(3b - 7) = -4 - 2(b + 3), b=3

Solve for x

3. -(3x - 2) = -(x - 4), x=-1

Solve for r

4. -7(r + 4) - 5r = -4(1 + 2r), r=-6

Solve for b

5. -2 - 5b + 1 + 8b = -8(-3 - 6b) - 5(8 + 6b), b=1

Whoops typo, I meant r=10. I know the answer is 66, how do I show the work by hand without a calculator?

Just go left to right divide 4/9 then multiply it by 18, you don't need to divide again because it is one.

47 days because of the size getting doubled every day. :D