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\((\frac{1}{2}){}^{3}=\frac{1}{2}*\frac{1}{2}*\frac{1}{2}=\frac{1}{8}\)

82377

The 2nd buton gives the inverse of the sin....

when you pust the 2nd button , you will see the sin button change to 'asin'   which is arcsin  also written as  sin^(-1)

if you have an angle and you know the sin is .34 and you need to find the angle ,  enter '.34' then push 2nd button then asin button, then ' = '

Hmmmm... I think you may have something wrong here....

39.26/138  = 18/sin(x)    

sin(x) = 18 / (39.26/138) = 63.27     cannot happen.....sin only goes fro -1 to +1.....  Do you have any more information?

what is 1e+200 in numbers =10^200

Who is Stampy fan #1

7/[7+18] =7/25 =.28 x 100 =28% of the class are girls.

Max: see the explanation of !n here:

http://www.wolframalpha.com/input/?i=What+does+!n+mean%3F

I agree with Max, since you asked for SPEED.   If you had asked for VELOCITY, (which is a vector), all of those angles WOULD matter !

Max: The final result should be:8x - 3 not 8x + 3.

78354962*776625 = 60852422363250 according to this calculator.

Max: Sorry for my ignorance, but what does that "squiggle" between a and b mean?

The definition of derivative is \(\displaystyle\lim_{\Delta x \rightarrow 0}\dfrac{f(x+\Delta x)-f(x)}{\Delta x}\)

Let f(x) = 4x^2 - 3x.

\(\quad f'(x)\\ =\displaystyle\lim_{\Delta x \rightarrow 0}\dfrac{f(x+\Delta x)-f(x)}{\Delta x}\\ =\displaystyle\lim_{\Delta x \rightarrow 0}\dfrac{(4(x+\Delta x)^2 - 3(x + \Delta x))-(4x^2-3x)}{\Delta x}\\ =\displaystyle\lim_{\Delta x \rightarrow 0}\dfrac{4x^2+4\Delta x^2 + 8x\Delta x - 3x - 3\Delta x-4x^2+3x}{\Delta x}\\ =\displaystyle\lim_{\Delta x \rightarrow 0}\dfrac{4\Delta x^2 + 8x\Delta x - 3\Delta x}{\Delta x}\\ =\displaystyle\lim_{\Delta x \rightarrow 0}4\Delta x + 8x - 3\\ = 4(0) + 8x + 3\\ = 8x + 3\)

\(7\bowtie g\\ = 7 + \sqrt{g+\sqrt{g+\sqrt{g+\cdot\cdot\cdot}}}\)

That means the whole thing after the 7 must be equal 2.

The dots means extended to infinity.

Therefore let \(x=\sqrt{g+\sqrt{g+\sqrt{g+\cdot\cdot\cdot}}}\)(it equals 2 at the same time.)

\(\sqrt{g+x} = x\\\sqrt{g+2} = 2\\ g + 2 = 4\\ g = 2\)

Finished!!

I think you may know factorization of quadratics so I skipped the steps.

\(\quad n^2 + n - 20\\ = n^2 + 5n - 4n - 20\\ = n(n+5) -4(n+5)\\ =(n-4)(n+5)\)

How does

\({n}^{2}+n-20=0\)

become

\((n+5)*(n-4) = 0\)

How did you come up with that?

I didn't know they were angles. Oops

I didn't know they were angles. Oops

The angle isn't the problem, the main thing is how far the object travels.

Total distance of the object travels 

= 100 + 50 + 50 + 170

= 370 ft

Speed of the object

\(=\dfrac{370ft}{5min}\\ = 74 ft/min\)

Example: you have y = 3x + 5

y = 3x + 5

y - 5 = 3x

x = y/3 - 5/3

Therefore the x-intercept is -5/3.

\(x + (1/5) x + (1/5)x + x = 180\\( 2 + (2/5))x =180\\ x = \dfrac{180}{\frac{12}{5}}=\dfrac{5}{12}\times 180 = 5 \times 15 = 75 \)

The expression is \(\dfrac{m}{2} + 7\)

2 is always 2.

I assume you mean 2x.

\(-\dfrac{4(3x+1)}{2(2x-4)}=\dfrac{1}{2}\\ \dfrac{4(3x+1)}{2(2x-4)}=-\dfrac{1}{2}\\ 24x + 8=8-4x\\ 28x = 0\\ x = 0\)

Therefore 2x = 0

You may mean \(2^x\) and \(2^x = 2^0 = 1\)