I can't see any straight forward way to do this.
The 4 dice would have to add up to 6,9,12,15,18,21 or 24
The only way for the dice to add to 24 is 6,6,6,6 that is one combination.
Add to 21
6,6,6,3
6,6,5,4
6,5,5,5, So there are 3 ways to add to 21
Add to 6
1,1,1,3
1,1,2,2 So there are only 2 ways to add to 6
Add to 9
1,1,1,6
1,1,2,5
1,1,3,4
1,2,2,4
1,2,3,3 that is it I think so that is 5 ways
Add to 12
1,1,4,6,
1,1,5,5
1,2,3,6
1,2,4,5
2,2,2,6
2,2,3,5
2,2,4,4
2,3,3,4
3,3,3,3 that seems to be 9 ways
Add to 15
1,2,6,6
1,3,5,6
1,4,5,5
1,4,4,6
2,2,5,6
2,3,4,6
2,3,5,5
2,4,4,5
3,3,3,6
3,3,4,5
3,4,4,4 there seems to be 11 there
add to 18 (I am going to try and do it differently - in pairs this time)
6+12 1,5,6,6
2,4,6,6
3,3,6,6
7+11 1,6,5,6
2,5,5,6
8+10 6,2,6,4
6,2,5,5
5,3,4,6
5,3,5,5
4,4,4,6
4,4,5,5
9+9 6,3,6,3,
6,3,4,5 That seems to be 11 ways
6 2 ways
9 5 ways
12 9 ways
15 11 ways
18 11 ways
21 3 ways
24 1 way
So if I haven't made any mistakes I get 2+5+9+11+11+3+1 =2+5+9+11+11+3+1
= 42 ways of thowing a multiple of 3