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This will not be linear.....thus any regession type equation will not perfectly fit the data...I used this app to create an (approximate) equation :   http://www.alcula.com/calculators/statistics/linear-regression/

This equation gets close

 y=1400+162x   where x is the bridge length and y is the cost of painting

No!. Googol factorial is bigger than Googolplex by about a Googol (10^100). You can determine this by using "Stirling's Formula" : n!~Sqrt(2.Pi.n).(n/e)^n. You can use this formula by taking the Logs of both numbers.

the Q is 

find x,y€R and verfy the:

x+yi / x-yi = x-yi

Googolplex is bigger, by a googol-2 0s factorial, because the sheer number of zeros cancel down. 

Yours, a year 10 (first year of GCSE)

x + x^2 =x + x^2 =x(x +1)

1/x + 1/y = 1/2016. Well, one obvious solution is:

x =4032 and y =4032!!!!!!,because

1/4032 + 1/4032 = 1/2016

sin2x can be written as 2sinx*cosx, so sin2x/(2sinx) → cosx 

(this is, in fact, defined at x = 0)

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Let x = 0.013013013...

Then 1000x = 13.013013013...

Subtract x from 10x to get:   999x = 13

So x = 13/999

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(x^2 - x - 6)/(x^2 - 4) → (x - 3)(x + 2)/( (x - 2)(x + 2) )  → (x - 3)/(x - 2)

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If both letters are different and all the numbers are different then there are 5! = 120 different possibilities.

If both letters can be the same,then there are 5!/2! ways.

If both letters can be the same and the three numbers can be the same then there are 5!/(2!*3!) ways.

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4y=x+8

y+3=1/4x+3

s=v*t=9,8m/s*90s=882m=0,882km

Prob of none left handed:   0.92^20

Prob exactly 1 left handed:   0.08*(0.92^19)*20    (20 because there are 20 ways of choosing the 1)

Prob exactly 2 left handed:  (0.08^2)*(0.92^18)*190.  (190 because there are ncr(20,2) = 190 ways of choosing a pair)

Sum the three probabilities above to get the probability of "at most" 2.

if 4/3x - 1/2 = 0     add 1/2 to both sides

4/3x = 1/2             divide both sides by 4/3

x = 1/2 / 4/3

x =1/2 x 3/4

x = 3/8

Your equations are wrong!. No solutions exist!.

at 1 pm there where 16 seagulls on the beach. at 3 pm there where 40 seagulls. what is the constant rate of change

3 - 1 = 2 hours past

40 - 16 = 24 increase in bird numbers in 2 hours

24 / 2 = 12 birds per hour - constant rate of change.

2v+7=3    subtract 7 from both sides

2v =3 - 7

2v = - 4    divide both sides by 2

v = -4/2

v = - 2

5/12:2/4=x:18

(5/12) / (2/4) x 18 = 15

5/12:2/4 =15:18

243*b^3=9     divide both sides by 243

b^3 =1 / 27     take the cube root of both sides

b =(1/27)^1/3

b = 1/3

243*b^3=9     divide both sides by 243

b^3 =1 / 27     take the cube root of both sides

b =(1/27)^1/3

b = 1/3

1544000/((1+r)^8)=504736   cross multiply

504736(1+r)^8 = 1544000     divide both sides by 504736

(1+r)^8 = 3.0590249              take the 8th root of both sides

1+r = 3.0590249^(1/8)

1+r = 1.15                              subtract 1 from both sides

r = 1.15 - 1

r = 0.15 x 100                         multiply by 100

r = 15%             

nothing

$3.60

It may only seem that to you. Math is complex in many different ways. There is really no explanation to that.