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don't spam

have no idea what that guy is talking about

3.141592653589793238462643383279502884197169399375105820974944

sin 4x   = (4sinxcosx) (2cos^2 (2x) - 1 )

4sinxcosx  =  2*2sinxcosx = 2sin2x

2cos^2(2x) - 1 =   cos(4x)

But.....as the graph below shows,

sin (4x)   is not equal to   2sin(2x)cos(4x)

So....this is not an identity.....

If you want to simplify, you get \(-a^2\)

If you want an exact answer it is:

\(\frac{26\sqrt{10}}{5}\)

This is how I got it:

\(\sqrt{270.4}=\sqrt{\frac{1352}{5}} \\ = \frac{\sqrt{1352}}{\sqrt{5}} \\ = \frac{26\sqrt{2}}{\sqrt{5}} \\ = \frac{26\sqrt{2}(\sqrt{5})}{\sqrt{5}(\sqrt{5})} \\ = \frac{26\sqrt{10}}{5}\)

Um, ok?

-441 is the answer, like what CrazyChippy said.

Okay that makes sense. Thanks :)

\(\frac{5y}{z}-\frac{2y^2}{3z^5} \\ \text{If z is 0 then the problem is undefined. So z ≠ 0.} \\ \frac{5y(3z^4)}{z(3z^4)}-\frac{2y^2}{3z^5} \\ \frac{15yz^4-2y^2}{3z^5}\)

As far as I can tell that is it in the simplest form, and the only restriction is z ≠ 0.

That is what I got but I don't really know what the definition of "simple" is sometimes.

1.6444

Does it simplify to:15yz^4-2y^2/3z^5?

sin x = 0.6691

x = arcsin(0.6691)

x₁ ≈ 41.998º

This is only the angle that makes the sinx  = 0.6691 in the first quadrant.

The other angle that makes sinx = 0.6691 will be in the second quadrant.

The third and fouth quadrants all have negative sin values.

So to find the other angle all you gotta do is subtract  41.998º from 180º

x₂ ≈ 180 - 41.998

x₂ ≈ 138.002°

-441.

{kanye=(((((sqrt(79)*west)*sqrt(4*west^2+6399))/6)+((2*west^3+6399*west)/54))^((1/3)))+(west^2/(9*((((sqrt(79)*west)*sqrt(4*west^2+6399))/6)+((2*west^3+6399*west)/54))^((1/3))))-(((2*west)/3)), kanye=(-(((sqrt(3)*i)/2))-((1/2)))*((((sqrt(79)*west)*sqrt(4*west^2+6399))/6)+((2*west^3+6399*west)/54))^((1/3))+(((((sqrt(3)*i)/2)-((1/2)))*west^2)/(9*((((sqrt(79)*west)*sqrt(4*west^2+6399))/6)+((2*west^3+6399*west)/54))^((1/3))))-(((2*west)/3)), kanye=(((sqrt(3)*i)/2)-((1/2)))*((((sqrt(79)*west)*sqrt(4*west^2+6399))/6)+((2*west^3+6399*west)/54))^((1/3))+(((-(((sqrt(3)*i)/2))-((1/2)))*west^2)/(9*((((sqrt(79)*west)*sqrt(4*west^2+6399))/6)+((2*west^3+6399*west)/54))^((1/3))))-(((2*west)/3))}

\(\frac{x^2 +x+1}{x+1}=x+2 \\ x^2 + x + 1 = (x+2)(x+1) \\ x^2 +x+1=x^2+3x+2 \\ 0 = x^2 +3x +2 -(x^2 +x+1) \\ 0 = x^2 +3x +2 -x^2 -x-1 \\ 0 = 2x+1 \\ -1 = 2x \\ -\frac{1}{2}=x\)

x^2 - 6x + 5 ≥ 0 

Set this to 0

x^2 - 6x + 5  = 0       factor

(x - 5) ( x - 1)  = 0   set each factor to  0   and solve  and x = 5 and x =1

The solution to the original inequality will come from either of these two intervals (-inf,1] and [5, inf) or from the interval  [1, 5]

Note that testing any point between x = 1 and x = 5 will make the inequality false

So.....the solution is   x = (-inf, 1] U [5, inf )

The value of the ratio of the circurmference to a circle to its diameter. It's an irrational number, so it never ends. (3.14159265358979...)

It's also the sixteenth letter of the Greek alphabet, but I'm presuming that wasn't what you meant by pi. xD

Thanks! :D

-And yes, it was a 5-day work week. Probably should've specified that. :P

If your question was, "What percentage is 2 of 7?"

First, type " 2/7 " into the calculator.

Second, multiply by 100 (or just move the decimal to the right 2 places).

2 is about 28.6% of 7.

Here's another example:

"74 is what percent of 30?"

First, type " 74/30 " into the calculator.

Second, multiply by 100.

74 is about 246.7% of 30

A lot of times I can't remember how to do percents so I just have to go back to what "percent" really means. "Cent" means 100. (A century is 100 years. One cent is one hundredth of a dollar.) Percent literally means per 100.

The question is "2 out of 7 is what out of a hundred?" In other words, if you had 2 out of 7 people with red hair, how many people would have red hair out of 100? How many people would have red hair per 100 people?

This is how to set that up:

\(\frac{2}{7} = \frac{x}{100}\)

Then you solve for x. 200/7 is exactly what we had earlier.

I still go back to thinking of percentages like this just because it is the easiest way for me to think of it.

Lol I realize you probably didn't need a one page essay on this but I just thought I'd share all that.

22222222222222222

Thanks, MJ.......welcome, CC  !!!!!

[ x^2 + 2x + 3] / [ x + 4]  =  [ x + 5]      multiply both sides by x + 4

x^2 + 2x + 3  =  x^2 + 9x + 20     subtract x^2 from both sides

2x + 3  = 9x + 20       subtract, 9x, 3 from both sides

-7x  = 17     divide both sides by -7

x  = -17 / 7

I'm assuming a 5-day work week...

The number of hours he works per week  =   4(8) + 9  = 41 hrs

If he mines 3 pieces per hour.....he mines  41(3)  =  123 pieces mined per week

And he has left to be mined = 41 pieces 

And it will take him    41/3  ≈ 13 + 2/3    overtime hours to mine all the coal he has found

So he mines 41(4)  = 164 pieces in  41 + 13 + 2/3  =  54 + 2/3 hours

Note that it will take him  196/3 ≈ 65 + 1/3 hours to meet his quota if he only mines 3 pieces per hour....thus....he cannot meet his quota, even with the overtime hours