Circle O has center (5,5) and radius 4. Circle P has center (3,-1) and radius 5. Which describes how circle O can be transformed so that circle O is similar to circle P?
\(m=\) \(\frac{y_o-y_p}{x_o-x_p}=\frac{5-(-1)}{5-3}\) \(=3\)
\(y=mx+b\)
\(b=\) \(y-mx\) = \(5-3\times5\) = \(-1-3\times3\) = \(-10\)
\(y=3x-10\)
\(d=\sqrt{(y_o-y_p)^2+(x_o-x_p)^2}=\sqrt{(5-(-1))^2+(5-3)^2}=\sqrt{36+4}=\sqrt{40}\)
\(d=6.324555\)
For the conglomeration with circle O
move the circle P upwards on the straight line
y = 3x - 10
by
d = 6.324555
!
