Since the area of the lawn = area of the store.... the area of the store must occupy 1/2 of the lot = (1/2)(70 * 45) = 1575m^2
So....let x be the width of the walk...so the area of the store can be represented by
(70 - 2x) (45 - 2x) = 1575
Solving this for x we have that x ≈ 7.9459 m = the width of the walk
The dimesions of the store are :
70 - 2(7.9459) = 54.1082 m
45 -2(7.9459) = 29.1082 m
So the dimensions of the store are 54.1082m x 29.1082m
