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If you graphed y = k, it would be a straight horizontal line.

Every place f(x) touches that line, f(x) equals k right there.

At every point that f(x) touches the line y = k, there is a solution for f(x) = k.

The question is basically: where could you put a straight horizontal line so that f(x) touches it 3 times?

Does that help any? If you want more help just say so :)

Don't you think you should give us some idea or hint as to what you are trying to calculate? Stringing a bunch of "Phis" together doesn't tell us anything!!. Oh, another thing. Try typing it with ordinary print, so we can enter it in computers and see if we get anything back. We can't copy and paste as it's written. This is strictly the opinion of one "Guest." Good luck.

Triangles can be classified either according to their sides or according to their angles. All of each may be of different or the same sizes; any two sides or angles may be of the same size; there may be one distinctive angle. 

Equilateral triangle: A triangle with all three sides equal in measure. 

Isosceles triangle: A triangle in which at least two sides have equal measure 

Scalene triangle: A triangle with all three sides of different measures

Right triangle: A triangle that has a right angle in its interior 

Acute triangle: A triangle having all acute angles (less than 90°) in its interior

Equiangular triangle: A triangle having all angles of equal measure 

This can probably explain it better than I can:

triangles

I just did 11 / 30 in the calculator. 

Just like:

three fourths of a dollar = 3/4 of a dollar = 0.75 of a dollar

eleven thirtieths of a dollar = 11/30 of a dollar ≈ 0.37 of a dollar

If this guy has like 12 ducks, and he tags them. then he gets like 20 ducks the next day and there are 6 tagged, how many DUCKS are there?!?!

Your question is very poorly written but I think i know what you mean.

there are 12 tagged ducks  and 6/20 of the ducks appear to be tagged so

\(\frac{6}{20}=\frac{12}{x}\\ 6x=240\\ x=40\)

So there is about 40 ducks altogether.

A woman is 4 times as old as her daughter. In 12 years time, the sum of their ages will be 89. How old was the woman when her daughter was born?

Let the daughter's age =D

Her mother's age =4D

D+12+4D+12 =89

5D =89 - 24

5D =65

D = 65/5

D=13 years - daughter's age now

13 x 4 =52 mother's age now.

52 - 13 =39 years - mother's age when her daughter was born.

Surface area of what?

 well this is kind of like really easy question the answer will be zero(0)...

well you need to know the mesurments of ingreadeints you are puting in it

 it is really easy it is two(2) are you just testing us out?

it is not polite to call others stupid that is why other people do not respond

How you actually calculated that?

all you have to do is multiply the numeraters by the other numeraters if the denominator is the same...

too clever

\((54y)^{\frac23}=\sqrt[3]{(54y)^2}=\sqrt[3]{2916y^2}=9\sqrt[3]{4y^2}\)

Hey to answer the question we need to see the rectangle. what is the formula on one side?

If you assume that the size of the Universe, before big bang, was about 10^-40 meters, then

10^-40 * e^x =.84, solve for x

x~90, or about 132 doublings in 10^-36 seconds!!.

A Stem and Leaf Plot is a special table where each data value is split into a "stem" (the first digit or digits) and a "leaf" (usually the last digit). 

The "stem" values are listed down, and the "leaf" values go right (or left) from the stem values.

The "stem" is used to group the scores and each "leaf" shows the individual scores within each group.