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PLEASE HELP ME

At least one of your answers is incorrect. Determine which regions of the Venn diagram, if  any, are given in the problem statement. Enter those values in the appropriate regions.

thanks

Just divide each amount by 9....so.....

Monday     12 / 9  =  4 / 3  = 1 + 1/3 batches

Tuesday   22 +  1/2  =  45/2

So        (45/2) / 9  =  45 / 18  =   5/2    =  2 + 1/2 batches

Thurssday    6 / 9   =  2 / 3  batches

Friday   7 + 1/2   =   15/2

So       (15/2) / 9  =  15 / 18   =   5 / 6   batches

nice to know! great!

The area of ABCD  =  AB *  BC      .... so...

140  = 14 * BC     divide both sides by 14

10  = BC  = height of ABE

So....area of ABE  =   

(1/2) AB * BC  =  (1/2) 140  =   70  in^2

A  = x - 26

B = 2x - 227

C =  x / 2   +  13

These sum to  180.....so

 [x - 26]   + [ 2x - 227]  + [ x/2 + 13]   =   180       simplify

3.5x - 240  =  180        add  240 to both sides

3.5x  = 420       divide both sides by 3.5

x  =  120

So  A   =  120 - 26    =     94°

Wow! This pattern that you have displayed actually continues past 7, actually, as I discovered just now. You just have to perform an intermediary manipulation.

\(142857*8=1142856\Rightarrow1+142856=142857\)

\(142857*9=1285713\Rightarrow1+285713=285714\)

\(142857*10=1428570\Rightarrow1+428570=428571\)

It seems to be that any multiple of 7 results in the 999999 result while anything else results in this "cyclic" property.

\(142857*77=10999989\Rightarrow10+999989=999999\)

Here are a few arbitrary attempts I tried to see if the pattern maintained itself. To my relief, it does. 

\(142857*43=6142851\Rightarrow6+142851=142857\)

\(142857*6807=972427599\Rightarrow972+427599=428571\)

\(142857*142857=20408122449\Rightarrow20408+122449=142857\)

Amazingly, this pattern maintains itself for incredibly large multipliers. It requires more manipulation, though. This is incredible!

\(142857*758241142857=108320054945122449\Rightarrow108320054945+122449=108320177394\\ 108320177394\Rightarrow108320+177394=285714 \)

A 9 ft post casts a 7 ft shadow.

A 45 ft tree casts a 35 ft shadow.  

sorry, got it backwards !!

The radius of the larger circle is  20 cm

So  it's area  is   pi (20)^2  =  400pi cm^2      (1)

The area of both of the smaller circles is

2 * pi (10)^2  =  200 pi cm^2    (2)

So  the shaded area  is  (1)  - (2)  =

[ 400 - 200 ] pi  cm^2    =

200 pi   cm^2  =

200 * (3.14) cm^2 =

628 cm^2

C = 28pi    ft

C  =  2pi *r        so

28pi  =  2pi *r       divide both sides by 2pi

14 feet  = r

28 feet  = d

Area  =  pi * (r)^2   =  pi * (14)^2   =   196pi  ft^2

Let H be the tree height....so we have

H / 35  =  9 / 7      multiply both sides by 35

H  =  (35 * 9)  / 7   =  (35/7) * 9  =  5 * 9  =  45 ft

some came out wrong 

To find the number of inches, take the decimal portion of the measurement and multiply by 12.

Count the letters in each word of the question

Find = 4

the = 3

sum = 3

of = 2

the = 3

two = 3

missing = 7

numbers = 7

in = 2

the = 3

sequence = 8 

therefore the sum of the next two numbers (3,8) is 11

The diagonal will be the hypotenuse of a right triangle...so..its length is

√  [ 22^2  + 6^2  ] =

√ [ 484 + 36 ] =

√ 520  ≈  

22.8 ft

.8  of 1 foot  =   .8 * 12  inches  =  9.6 in

So...the length is ≈    22ft  9.6 in

one of them is incorrect

2n ,  n^2   - 1, n^2  + 1

2*7  , 7^2 - 1 ,  7^2  + 1

14 , 48,  50

Edit to correct an error.....!!!

Yes !! 142857

142857 x 1 =142,857

142857 x 2 =285,714 same numbers in different order.

142857 x 3 =428,571  ...................................................

142857 x 4 =571,428.....................................................

142857 x 5 =714,285......................................................

142857 x 6 =857,142......................................................

142857 x 7 =999,999  !!!

7  ,     (7^2 - 1) /  2   ,  (7^2  + 1) / 2  =

7   ,         48/2         ,          50/2         =  

7    ,         24          ,           25   

Not sure about the first one, J....but the second is this :

The angle in rads is given by :

arctan (2/4)  + pi/2  =

arctan (1/2) + pi/2  =  

2.034 rads

So....you are correct.......!!!!

We have the following proportion :

19 / 50   =  h / 325   where h is the building height

Multiply both sides by 325  and we have

h  =  [ 325 * 19 ] / 50  = 123.5 ft

Draw BD....   and this forms a hypotenuse of  triangles ABD  and triangles BDC

In triangle   ABD , we can find BD using the Pythagorean Theorem

BD  =  √[ AD^2 + AB^2 ]  = √ [ 12^2 + 5^2 ]  = √ [ 144 + 25]  = √169  = 13

And  using the same theorem, in triangle BDC, leg DC can be found as

DC  =  √ [ BD^2  - BC^2]  = √ [ 13^2 - 11^2]  = √ [169 - 121]  = √48 = √[16 * 3]  =

√16 * √3  =  4√3

And the area of each right triangle = (1/2)(product of the legs)

So....the total area  =  (1/2)(12 * 5) + (1/2) (11 * 4√3)  =

(1/2) [ (12*5) +  (11 * 4√3) ]  =

(1/2)  [ 60 + 44√3]  =

[30 + 22√3]  sq units