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I know CPhil got to this before me, but I want to gve this a try before I see the answer.

Is it $30+5.5\sqrt{26}$?

7/ 9 x 35 =27 2/9 Ft - the height of the tree.

Okay thanks :D 

The dimensions of the photograph are proportional to the dimensions of the land:

If the shortest side =240 m

240 / 4 x 6 =360 m

360/ 6 x 9  =540 m, so that:

240:360:540 =4:6:9

There are 4 periods in each second

So....eaach period lasts 1/4 seconds

At t = 0,  let the height = 1 m 

So...at  1/16 seconds  the max ht is reached

At 2/16 seconds the height returns to 1m

At 3/16 seconds, the min height is reached  = 1m - .03m  = .97m

And at 4/16 = 1/4 second it returns to a height of 1m 

Note that the sin is maxed at pi/2

So....at  1/16 seconds....we have that  .03 sin (8pi *1 /16) + 1  =  .03sin (8pi/16) + 1  =

.03sin (pi/2) + 1 =  .03(1) + 1  =   .03 + 1  =  1.03m

So.....the function  is

h(t)   =  sin ( 8pi * t)  +  1    =   choice " a "

See the graph here :  

https://www.desmos.com/calculator/f9yuhgchgr

Hello Sprite, 

You know, you could just say it's rude to delete your post blab blah etc jabber on and then post back my question right? But no, you didn't. Instead, you acted like ginger. Very bitter, and nasty. What you're telling me, is that if CPhill or Melody weren't going to hide unethical comments as such, why would you want to make them in the first place? Bad character I suppose. I would try to start acting like Fanta, very nice and sweet <3. 

Kind Regards, 

Julius 

This is a diagram for you to reference as I solve for the radius, r.

 $C=6r+14.84$ because of what the given info states. The general formula for the relation of the radius and circumference is $C=2\pi r$, so $2\pi r=6r+14.84$. Now, solve for r, in feet.

There is nothing to solve !!  We can simplify it a bit?

Simplify the following:
x/4 - (5 y)/2 + 3/x

Put each term in x/4 - (5 y)/2 + 3/x over the common denominator 4 x: x/4 - (5 y)/2 + 3/x = x^2/(4 x) - (10 x y)/(4 x) + 12/(4 x):
x^2/(4 x) - (10 x y)/(4 x) + 12/(4 x)

x^2/(4 x) - (10 x y)/(4 x) + 12/(4 x) = (x^2 - 10 x y + 12)/(4 x):

(x^2 - 10xy + 12)/(4x)

Similar triangles have equal corresponding angles...so....

 Δ ABC  is similar to  Δ NMP

Angle A  = Angle N  =  180  - 30 - 85  = 65° 

Angle M  = Angle B  = 85°

Angle P  = Angle C  = 30°

The square root sign is ambiguous in your second question. Can you tell me which equation you mean?

A) $\sqrt{2x}-4-x+6=0$

B) $\sqrt{2x-4}-x+6=0$

C) $\sqrt{2x-4-x}+6=0$

D) $\sqrt{2x-4-x+6}=0$

Without knowing this, it will be very difficult to help you out.

Solve for r:
0 = 10 - r/-1  cross multiply

0 = 10 - r is equivalent to 10 - r = 0:
10 - r = 0

-r =-10   multiply both sides by -1

r = 10

By the exterior angle theorem.....angle BCD  = angle A + angle B  ....so....

138x - 1   =  101x + 2  + 34x       simplify

138x - 1  =  135x + 2        subtract 135x from both sides, add 1 to both sides

3x  =  3    divide both sides by 3

x  = 1

So   BCD  =  138(1) - 1   =   137°

(101x + 2) + 34x + C = 180, solve for C
C =178 - 135x
(178-135x) + (138x - 1) = 180, solve for x
x = 1, so:
Angle BCD =(138x1 -1) =137 Degrees.

A  =  x

B  = 5x

C = 4x - 2

These angles sum to 180....so we have that...

x  + 5x  + (4x - 2)   =   180     simplify

10x - 2 =  180      add 2 to both sides

10x  =  182     divide both sides by 10

x  = 18.2°  =  A

5(18.2)  =  91°  =  B

4(18.2) - 2  =  70.8° =  C

It is generally considered standard to write polynomials from highest degree to least degree, so your method of multiplying the first term in every polynomial would be sufficient. However, the first polynomial actually has a degree of 7

($x^4+\textcolor{red}{ax^7}+bx+c$). Notice that the highest-degree term is actually listed second.

Therefore, I would amend your rule slightly. Add the degree of each polynomial together during multiplication. Doing this will give you the degree of $(x^4+\textcolor{red}{ax^7}+bx+c)(\textcolor{red}{x^3}+dx^2+e)(\textcolor{red}{x}+f)$ or any other product of multiple polynomials. Notice that I have highlighted, in red, the term that dictates the degree of the individual polynomials. If we use the rule that I aforementioned, then the degree equals $7+3+1=11$.

Hey, thanks dude!

Kinda' hard to see...LOL!!!...but...

Angle  7   = Angle 12  = Angle 5  = Angle 1   =  56° 

Angle 2  =  63°

Angle 9 = Angle 4  = Angle 3  =  61° 

Angle 10  = Angle 6  =  180 - 61  = 119°

Angle 8 = Angle 11  =  180 - 56  =  124°

Solve for t:

(10 + t x + 4 x^2) (5 x^2 - 6 x + 7) = 20 x^4 - 54 x^3 + 114 x^2 - 102 x + 70

Divide both sides by 5 x^2 - 6 x + 7:

10 + t x + 4 x^2 = (20 x^4 - 54 x^3 + 114 x^2 - 102 x + 70)/(5 x^2 - 6 x + 7)

Subtract 4 x^2 + 10 from both sides:

t x = -6 x

Divide both sides by x:
t = -6

Your question is a tad too vague for me to help you directly here. Does "y=mx+c equation for Line on a graph" mean graphing an equation in "y=mx+c-form," generating the equation in y=mx+c given two points, converting from point-slope form to y=mx+c form, or something else?

Congratulations!

If i read this correctly.....one angle measures  ( x + 1)°  and the other measures (4x - 56)°

These two angles will sum to 180°

So we have

( x + 1 )  + ( 4x  - 56)  = 180     simplify

5x- 55   =  180       add  55 to both sides

5x  =  235         divide both sides by 5

x  = 47

So...one angle measures   (47 + 1)  = 48°

And the other measures  (4 (47) - 56 )   =  ( 188 - 56)  =  132°

10 x 8 =80 square feet - area of the first room

$300 / 80 =$3.75 - cost of carpet per square foot.

20 x 16 =320 square feet - the area of the second room

320 x $3.75 =$1,200 cost of carpeting the second room.

C  = 2r  +  205.44    (1)  and  C  =  2 * 314 * r     (2)

Set (1)  =  (2)   and we have that

2r + 205.44  =  2 * 3.14 * r     simplify the right side

2r + 205.44  =  6.28r       subtract  2r from each side

205.44  =  4.28r       divide both sides by  4.28

48  =  r      [ the radius is 48 ft ]

Circumference = Diameter x Pi

C = 12 x Pi - Feet

D = 12 Feet 

Radius = Diameter / 2

R = 12 / 2 = 6 Feet

Area =Radius^2 x Pi

Area =6^2 x 3.141592

Area =36Pi - Square feet, or ft^2.