2.In rhombus ABCD, points E, F, G and H are the midpoints of AB, BC, CD, DA and respectively. Quadrilateral EFGH has area 14 and perimeter 16. Find the side length for rhombus ABCD.
The side length will = the diagonal length of the quadrilateral
So
Area of quadrilateral LW = 14 (1)
Perimeter of quadrilateral = 16 = 2(L + W) ⇒ 8 = L + W ⇒ L = 8 - W (2)
Sub (2) into (1)
(8 - W) W = 14 simplify and rearrange
W^2 - 8W + 14 = 0
Solving this for W gives us both dimensions of
4 + √2 units and 4 - √2 units
And the length of a side of the rhombus is
√ [ ( 4 + √2)^2 + ( 4 - √2)^2 ] =
√ [ 16 + 2 + 16 + 2 ] = √36 = 6 units