All Answers 358149 Answers

that is interesting.  I got the same answer but on the surface our forumulas look different.

$$\begin{array}{rll}
A&=&M \left(\dfrac{1-(1+i)^{-n}}{i}\right)\\\\
A\times \dfrac {i}{1-(1+i)^{-n}}&=&M\\\\
M&=&A\times \dfrac {i}{1-(1+i)^{-n}}\\\\
M&=&20000\times \dfrac {0.00575}{1-(1.00575)^{-60}}\\\\
M&\approx &\$ $395.08
\end{array}$$

If it is anything like :

How many web2 users getting the exact same answer does it take before a probability question can be declared correct. Well - it is a lot more than 3!

If u want to convert a to am , the easiest method is to write a and then write m just beside it like this :

a   

= am 

so now here u go with ur answer, we have converted a to am !

seven slips of paper with the number 5 through 11 are placed in a box after mixing two slips are drawn list the different combinations

This is the best way to list them.

5,6

5,7

5,8

5,9

5,10

5,11

-----

6,7

6,8

6,9

6,10

6,11

------

7,8

7,9

7,10

7,11

----

8,9

8,10

8,11

-----

9,10

9,11

-----

10,11

$$\boxed{{\ d{(\ln{y})} \over \ dx }={y' \over y }}\\\\
\Rightarrow {\ d{(\ln{x})} \over \ dx }={1 \over x }\\\\
\Rightarrow {\ d({\ln{(a\times x)}}) \over \ dx } ={a \over a\times x } ={1 \over x }$$

$$\begin{array}{ccl}
\int{ {1\over x} \ dx }&=& \ln{(|a\times x|)} +c_1\\
& = &\ln{(|a|)}+\ln{(|x|)}+c_1 \\
& = &\ln{(|x|)}+\underbrace{\ln{(|a|)}+c_1}_{c_2} \\
& = &\ln{(|x|)}+c_2}
\end{array}$$

Please do not ask the same question twice.

what does a 3 sided die look like?

 Are the two die different from one another in some way - like one red and one blue.  

Do the three sides all have something different on them?

All  2 questions are relevant.  But, assuming everything is different then CPhill answer is good.

Melody the question clearly means that his friend Bob ate his apples so let's not confuse ourselves ! 

Jerry had 28 apples and then his friend Bob ate two apples so:

28 -2 = 26 ANSWER

so now Jerry is left with 26 apples !

Melody if Bob had eaten someone else's apples then it would be given in the question and as nothing relating is given so let's not waste our time thinking this !

Hi Dragonslayer,

If it was the perimeter, that is the distance around the outside that was 12 units you would be correct but it is not.

It is the area that is 12 units.  That is the number of squares that fit inside.  so CPhill's answer is correct. 

U have 2 apples and then u buy three more which means

2+3=5   ANSWER

so now u have 5 apples !

Thank you Rose ! I have already have the test! I hope ur luck helps me !

This is AVERAGE acceleration of course.

Thanks jboy, The question askers should be encouraged to join in like this.

I think so anyway!

so I have given you a thumbs up for both your answers.  

$${\mathtt{1}}{\mathtt{\,-\,}}\left({\left({\frac{{\mathtt{176}}{!}}{{\mathtt{171}}{!}{\mathtt{\,\times\,}}({\mathtt{176}}{\mathtt{\,-\,}}{\mathtt{171}}){!}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{0.93}}}^{{\mathtt{171}}}{\mathtt{\,\times\,}}{{\mathtt{0.07}}}^{{\mathtt{5}}}{\mathtt{\,\small\textbf+\,}}{\left({\frac{{\mathtt{176}}{!}}{{\mathtt{172}}{!}{\mathtt{\,\times\,}}({\mathtt{176}}{\mathtt{\,-\,}}{\mathtt{172}}){!}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{0.93}}}^{{\mathtt{172}}}{\mathtt{\,\times\,}}{{\mathtt{0.07}}}^{{\mathtt{4}}}{\mathtt{\,\small\textbf+\,}}{\left({\frac{{\mathtt{176}}{!}}{{\mathtt{173}}{!}{\mathtt{\,\times\,}}({\mathtt{176}}{\mathtt{\,-\,}}{\mathtt{173}}){!}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{0.93}}}^{{\mathtt{173}}}{\mathtt{\,\times\,}}{{\mathtt{0.07}}}^{{\mathtt{3}}}{\mathtt{\,\small\textbf+\,}}{\left({\frac{{\mathtt{176}}{!}}{{\mathtt{174}}{!}{\mathtt{\,\times\,}}({\mathtt{176}}{\mathtt{\,-\,}}{\mathtt{174}}){!}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{0.93}}}^{{\mathtt{174}}}{\mathtt{\,\times\,}}{{\mathtt{0.07}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\left({\frac{{\mathtt{176}}{!}}{{\mathtt{175}}{!}{\mathtt{\,\times\,}}({\mathtt{176}}{\mathtt{\,-\,}}{\mathtt{175}}){!}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{0.93}}}^{{\mathtt{175}}}{\mathtt{\,\times\,}}{{\mathtt{0.07}}}^{{\mathtt{1}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{0.93}}}^{{\mathtt{176}}}\right) = {\mathtt{0.986\: \!001\: \!218\: \!893\: \!262\: \!3}}$$

$$P(enough\: seats )\approx 0.9860$$

I am reasonably sure that mine is correct. 

See Melody's calculation below.

I'll leave you to decide on the conclusion.

PS:  I don't know what you mean by "Use = .10 ..." in your question.

distance between points (2,-5) and (-3,0) ?

$$\begin{array}{crcrccr}
\mbox{Point 1:} \; &(x_1&=&-3,& y_1&=&0)\\
\mbox{Point 2:} \; &(x_2&=&2,& y_2&=&-5)
\end{array}$$

$$\begin{array}{ccl}
distance&=&\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\
distance&=&\sqrt{[2-(-3)]^2+[(-5)-0]^2}\\
&=&\sqrt{(2+3)^2+(-5)^2}\\
&=&\sqrt{(5)^2+(-5)^2}\\
&=&\sqrt{25+25}\\
&=&\sqrt{2*25}\\
&=&\sqrt{25*2}\\
&=&\sqrt{25}\sqrt{2}\\
distance&=&5\sqrt{2}\\
\end{array}$$

1/2+ 1 1/3+1 5/12  What does that equal?

$$\\{1\over 2}+ 1 {1\over 3}+1 {5\over 12}\\\\
={1\over 2}+ 1 +{1\over 3}+1 +{5\over 12}\\\\
=2+{1\over 2}+{1\over 3}+{5\over 12}\\\\
=2+
{1\over 2}
\times(
{3\over3}\times
{12\over12}
)
+
{1\over 3}
\times(
{2\over2}\times
{12\over12}
)
+
{5\over 12}
\times(
{2\over2}\times
{3\over3}
)
\\\\
=2+{5*12+5*6\over 2*3*12}\\\\
=2+{6\over6}\times{5*2+5\over 2*3*2}=2+{5*2+5\over 2*3*2}\\\\
=2+{15\over 12}=2+{3*5\over3*4}\\\\
=2+({3\over3})\times{5\over 4}=2+{5\over4}\\\\
=2+1+{1\over 4}=3+{1\over4}\\\\
=3{1\over4}$$

This question does not make any sense.

I am not happy about your answer Zegroes.  This question requires an explanation and your answer is just totally lazy!

Right on, Melody....it you try it, the first "integer" will be 33.5........this problem is missing something......

Do you mean a base 26?

It would not have to be base 26, you could do this just with base 10 but the numbers for the letters would be 1 to 26 or 0 to 25.  Maybe a hyphen could have a 27th value?

Unless consecutive can be interpreted differently form how I would interprete it this is impossible.

Consider just the 2nd and the 3rd integer.

One is even and one is odd.  When you add them you get an odd number.  

When you divide this by 2  you get something and a half.  It cannot be a whole number.

It would depend on whether Bob at Jerry's apples or his own apples.  Wouldn't it?

some people remember a formula for this, but I find it difficult to remember them so I work most things out.

This is how I might do it - I am treating it as a ratio.  I know that there are pi radians in 180 degrees.

$$\begin{array}{rll}
\frac{x}{330}&=&\frac{\pi}{180}\\\\
x&=&\frac{\pi\times 330}{180}\\\\
x&=&\frac{\pi\times 11}{6}\qquad \mbox{This is the exact number of radians}\\\\
\end{array}$$

$${\frac{{\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{330}}}{{\mathtt{180}}}} = {\mathtt{5.759\: \!586\: \!531\: \!581\: \!287\: \!6}}$$ 

approx 5.76 radians