All Answers 358149 Answers

Lets get a common denominator of 35 first

25/35-21/35=4/35

x =1 doesn't work.

(1/2)^1 = 1/2, and cos(1) does not equal 1/2.

I got still had the answer though I BEEN ROBBED OF MY POINTS!

MELODY.you just cant help puttin in your two cents cant you!

If born 1st July 2000 (for example), now 14.

If born 10th July 2000 (for example), still only 13.

60 degrees above the negative x axis means that we are in quadrant 2 so our x component will be negative.  TO find the x component we use the cosine function as it represents x values.  Our calculation looks like

V_x=12cos60=6

Sisyphus lends you a "0," zegroes.....

.0204081633

Now you're OK......

This appears to be linear......

Consider the slope between the first two points and then between the second and third points:

(2450 - 1100)/ (5-2) = 450      and

(3800 - 2450) / (8-5)  = 450

So the slope is the same, indicating a linear function.

Now, we can find the "y intercept" (where x = 0) by noting that everytime x changes by 1, y changes by 450. So when x changes from 2 to 0, y decreases from 1100 by (2 * 450) = 900. So 1100 - 900 = 200.

And the equation of our line is

y = 450x + 200

Yes Melody I just saw it and also posted some " supporting " words to my soooooo old friend ( as he thinks he is ) and fulfilled what I had said !  

YAY! Zegroes I won ! And as I said I'll support u so let me fulfill my words ! 

Zegroes don't worry , this happens sometimes , when u r too over confident ! So from now on don't be too over confident to beat your " younger" ones ! 

So those were my supporting words to my soooooo old friend!

By the way thanks for discovering the truth Melody ! Thumbs up from me ! 

Your Welcome!

For the month I'll say maybe but I don't think the day is required ! I just find out using the year only !

You would need to know the month and possibly the day as well.

Thanks Rosala,

What did I say, I have forgotten.

Did you see you got one right that Zegroes go wrong.  Chris got it wrong too because he said you were both correct!    

Yes Melody's right ! We would also get some nice and useful information ! 

Melody last time u gave me a useful advice for school ! Thank u very much it really helped ! Whenever I used to feel a lil weak or thirsty kind of then I used to think about ur advice and then it courageous me so since that day my days are going nice ! I don't feel too tired after returning from school! Thank u very much for the advice ! Thumbs up from me ! 

There wasn't a balanced number of brackets so I added one at the end.

$$((2^{1/2})*(2-3^{1/2})^{1/2}+3)^{-1/2}-(1-(2^{1/2})*((2-3^{1/2})^{1/2})^{1/2})\\\\
=((2^{1/2})*(2-3^{1/2})^{1/2}+3)^{-1/2}-(1-(2^{1/2})(2-3^{1/2})^{1/4})\\\\
=\frac{1}{((2^{1/2})*(2-3^{1/2})^{1/2}+3)^{1/2}}-(1-(2^{1/2})(2-3^{1/2})^{1/4})\\\\
=\dfrac{1}{\sqrt{\sqrt2 *\sqrt{(2-\sqrt3)}+3}}-\left(1-\sqrt2 \:\sqrt[4]{(2-\sqrt3}\:\right)\\\\$$

The site calcanswered what you wrote.  I answered something closer to what you may have meant.

I doubt that it was a serious question anyway so it really doesn't matter.   

$${\left({\frac{\left({\frac{{{\mathtt{2}}}^{{\mathtt{1}}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\left({\mathtt{2}}{\mathtt{\,-\,}}{\frac{{{\mathtt{3}}}^{{\mathtt{1}}}}{{\mathtt{2}}}}\right)}^{{\mathtt{1}}}}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\right)}^{{\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}}{\mathtt{\,-\,}}\left({\mathtt{1}}{\mathtt{\,-\,}}{\frac{\left({\frac{{{\mathtt{2}}}^{{\mathtt{1}}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\left({\frac{{\left({\mathtt{2}}{\mathtt{\,-\,}}{\frac{{{\mathtt{3}}}^{{\mathtt{1}}}}{{\mathtt{2}}}}\right)}^{{\mathtt{1}}}}{{\mathtt{2}}}}\right)}^{{\mathtt{1}}}}{{\mathtt{2}}}}\right) = -{\mathtt{0.320\: \!299\: \!803\: \!774\: \!770\: \!9}}$$

@@ End of Day Wrap - Wed/Thurs 3/6/14   Sydney, Australia   Time 11:30am       ♬              

Hi all,                                                                             ♬

Lots of great answers today from Rosala, Zegroes, CPhill, Jboy314, admin, Alan, SevenUP, Heureka and dragonSlayer554.  Thanks everyone.      ♬                                                                           ♬ 

Yesterday Zegroes earned his star.                     CONGRATULATIONS ZEGROES     

Rose98 and DragonSlayer554 are both new.  Welcome to web2.0calc forum.  We hope that you learn lots and enjoy yourselves here.                                                      ♬

I worked out how we can duck between the different language forums without having to sign in each time.    

I hae a German post in my watchlist and if i use this to gain access i can go to the german site without any hassles and then I can go back again via an English post in my watch list.  It is really cool!

This is the German post that i used.  I assume that it will work from there as well but I am not sure.

Why don't you google this and come back and tell us the answer ?

If you had set this out a lot better you would have had some answers way before now.

Plus it looks like you are just trying to get us to do all your home work for you - not a good look!

I will look at the first one for you

 A=5/4(h-1) 

Multiply both sides  by 4/5 and you get

4A/5= h-1

add 1 to both sides and you get

4A/5 +1 = h

h= (4A/5) +1

you do not actually need the brackets.  

Me too !    By the way thanks ! Forgot to say the last time ! 

Yes, I didn't notice that thank you Alan.

I do not think that will ever happen Rosala,

and I would never want it to happen either.  

Just read the values straight off the triangle.

for example 

SinA = opp/hyp = a/c = 5/13

etc

To remember the ratios it is 

Some old hags 

can't always hide

their old age

Which stand for:

sin=opp/hyp

cos=adj/hyp

tan=opp/adj

They are not both correct Chris.

Rosala is correct 1/49

Zegroes is wrong He wrote 0.204... when it should have been 0.0204....

Zegroes you need to be more careful!  You are letting Rosala show you up!

Looks like zegroes can "go cry in a corner" (his words not mine) 

and Rosala can be "a lil excited to beat zegroes"      

ROFLOL!