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with x =0, you know y=100

so only the bottom two have a point 0,100

then it is trial and error. 

plug in 2 for x and 0 for y, 

if that works then it is the bottom left one.

if not then it is the other one,

you could check the bottom right with -2,0 or 5,0 as well

but 5,0 is an assumption since the 5 isnt labled.

so i would do this

0=(2)^4 - 6(2)^3 - 11(2)^2 +60(2)+100

what i do is look to see if point 0,0 is included.

as in subsitute 0 for x and y

0 is <= 10 so 0,0 is shaded for that one

0 is not < -1, so 0,0 is not shaded for that one.

< implies a dotted line, where <= implise a solid line.

The lower right is the only one that fits all this.

You could also put each equation in y=mx+b and draw the lines.

Then plug in 0,0 to see which direction to shade.

y = 2x-1/x+5         First, solve for 'x'    

  yx+5y -2x = -1

yx - 2x= -5y -1

x(y-2)  = -5y-1

x = (-5y-1)/(y-2)    then switch the x's and y's to have the inverse f^-1 (x)

y = (-5x-1)/(x-2)             a = -5 c= 1      a/c -5/1 = -5

Thanks!

4.25*10^14=425 with twelve zeroes.

The derivative of

x^2 -5 =

2 x^(2-1) = 2x      Now substitute the value you have for x at your point  (3,4)

2(3) = 6

Thanks Guest!!

Thanks EP

Thank you EP!!

The roots of the equation are the values of 'x' which make it true

so   there are 3 possibilities for this Q

3x =0            then    x=0

(x+4) = 0      then     x = -4

(x-6) =o        then    x = 6

Use quadratic formula to find 

+ 11/4  i     or    - 11/4  i 

The standard form of a line   is   y= mx + b

    so she was trying to get the equation to the standard form

This is more than a complete circle....a complete circle is  2pi radians (or 360 degrees)...so you need a fraction that is greater than   2pi

  SO first and third options are no good.

Now as a ratio

420 is to 360     as   ? is to 2 pi     or:

420/360 = ? / 2pi

420/360 x 2pi = ?  = 840pi /360 = 7/3  pi

Tan = sin/cos

   sin and cos repeat their values at  pi intervals ...with a change of sign

so   tan x  will equal    tan (x+pi)    

2/5

Please don't post questions twice !  

See:

https://web2.0calc.com/questions/line-ef-passes-through-the-points-0-1-and-3-3-line_1

False....see your other  T  F  question.

true.

-b + sqrt(b^2 - 4ac)  /  2a     *    -b - sqrt(b^2 -4ac)  / 2a

b^2 -(b^2-4ac)  / 4a^2

4ac /  4a^2

c/a

Slope of first line = rise/run  =  y2-y1/(x2-x1)  =  (3-1)/(3-0) = 2/3

Slope of second line =  3/-2 = -3/2  

The second slope is the negative inverse of the first, so the lines are perpindicular

yes it is true bruh

yes it is

is that the correct answer?

a=l*w

l=5.5w

a=5.5w*w

a=5.5w^2

88=5.5w^2

w=4

l=w*5.5

l=4*5.5

l=22

What is \(-2?

Thank you!!