All Answers 358407 Answers

The drama club sold 1500 tickets for the end-of-year performance.
Admission prices were $12 for adults and $6 for students.
The total amount collected at the box office was $15,480.
How many students attended the play?

Let a = adults

Let s = students

\(\begin{array}{|lrcll|} \hline (1) & a + s &=& 1500 \\ & a &=& 1500 -s \\\\ (2) & 12 a + 6 s &=& 15480 \quad & | \quad : 12 \\ & a + \dfrac{s}{2} &=& 1290 \\ & a &=& 1290 - \dfrac{s}{2} \\\\ \hline (1) = (2): & a = 1290 - \dfrac{s}{2} &=& 1500 -s \\ & 1290 - \dfrac{s}{2} &=& 1500 -s \quad & | \quad + s \\ & 1290 +s - \dfrac{s}{2} &=& 1500 \quad & | \quad -1290 \\ & s - \dfrac{s}{2} &=& 1500 -1290 \\ & \dfrac{s}{2} &=& 210 \quad & | \quad * 2 \\ & \mathbf{ s} & \mathbf{=}& \mathbf{420} \\\\ & a &=& 1500 -s \\ & a &=& 1500 - 420 \\ & \mathbf{ a} & \mathbf{=}& \mathbf{ 1080 } \\ \hline \end{array}\)

420 students attended the play.

The total costs for a job can be calculated with the function k(d) = 165d + 125. kis the total cost in euros and d is the amount of days it takes to finish the job. 

a. What kind of fuction is k?

b. Calculate the value of the function k(3)

c. What does the answer of b. mean?

d. Calculate for which value the following function for d is possible k(d) = 1280

e. What does the answer of d. mean?

Ik ben Nederlands

How would both graphs look like if x would be -8?

I'm dutch haha :") Here is the actual exercise

What is your native language?

Thanking Gavin was good manners but I would be nice for you to state why you think it is incorrect.

I assume the answer in the back of your book was different, if so this is what you should say.

so you could have said.

Thanks a lot!  I think your answer is incorrect because it is different from the answer at the back of the text book, but thanks for your effort. Maybe it was just a little careless error.... ??

That would sound nicer    

That word 'think' with the explanation makes a big difference to the sound of it.

the diamiter of the sphere will be the length of the side of the cube(lets call it S) thus...

4/3*pi*(1/2s)^3        PI/6

___________   =  _____

s^3                           1

volume of a cone is 1/3*pi*r^2* h

12pi = 1/3*pi*r^2*4

r=3

circumfrence is pi*2r

circumfrence = 6pi

m = 1385+T

m-629 = 4(T-87)

(1385+T)-629 = 4(T-87)

756+T = 4t - 348

1104 = 3t

t = 368

m=1 n=3

1) no idea what the function is sorry.

2) the function is y=9x

so x = -8 would mean y = -72

V= Pi x r^2 x h

V =Pi x 1^2 x 1

V =Pi

V =Pi x  0.8^2 x 1.25

V =0.8Pi

1 - [0.8Pi/Pi] = 20% - absolute decrease in volume.

Decreased by 20%=100%-20%=80%

Increased by 25%, 25/100*80=20, so 80+20=100%

Thus, there is no change, .\(0\%\)

Hey guest!

I found my careless mistake, when I determined the probabilty for case 1. 

I fixed it and the answer should be right now!

Thanks a lot!  (It was incorrect, but thanks for putting in the effort to answer.)

Hey guest!

We can split this probabilty problem into two cases:

Case 1: Markov gets 3-6 on the die for the first roll and 1-2 on the die for the second roll. 

Case 2: Markov gets 1-2 on the die for the first roll and flips a head on the second turn. 

Then, we find the probabilty of each case and then find the sum. 

Case 1: 

There are six possible rolls on the die. We need to get 3, 4, 5, or 6 on the first roll, and 1 or 2 on the second. 

\(\frac23\cdot\frac13=\frac29\)

Case 2: 

There are six possible rolls on the die and two outcomes for the coin. 

\(\frac13\cdot\frac12=\frac16\)

Then, we find the sum of the cases to reach the desired result. 

\(\frac29+\frac16=\boxed{\frac7{18}}\)

I hope this helped,

Gavin

120 is wrong

OK, good man. Now, he says "What is the probability the two balls are the same color?" So, I think you have to add up the two probabilities together to answer his question: 9/25 + 4/25 =13/25 = 52%.

Yes, thank you, guest, forgot about that!!!

So, both are 6/10, thus \(\frac{6}{10}*\frac{6}{10}=\frac{9}{25}\).

And for the red, \(\frac{4}{10}*\frac{4}{10}=\frac{4}{25}\).

Thanks again, guest!

Why is the probability of a second ball 5/10 when its color is just recorded and put back in the bag? You still have 6 green balls and 4 red balls. So the second draw should still be 6/10. No?.

There is a pattern.

With a and b the question is   1/(the new base-1)

Look at the answers you get from this.

Think about this. then you should be able to surmise what the answer to c will be.

a) is 0.1 repeater.

What did you get for b?

So what is c?

That is ok, we all have to learn.

So long as you are always polite and you learn good forum manners quickly there will not be a problem. :)

Always remember to thank people (plus of course people like to get points). If you think the answer is wrong or you do not understand then say so! People actually LIKE you to do this, it shows that you are really trying to learn!

Even if you say you do not understand, or you think the answer is wrong, you can still thank the person for their time :)