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 #4
avatar+55 
+5
Jul 13, 2014
 #3
avatar+55 
+10
Jul 13, 2014
 #1
avatar+118723 
+5

I am just going to do the first one for you.    (Completed after Alan's comment below)

 

http://cs.selu.edu/~rbyrd/math/continuous/

$$A=Pe^{rt}$$

r=5%=0.05

A=2P

$$\begin{array}{rll}
2P&=&Pe^{0.05t}\\\\
2&=&e^{0.05t}\\\\
ln2&=&lne^{0.05t}\\\\
ln2&=&0.05t\\\\
0.05t&=&ln2\\\\
t&=&\frac{ln2}{0.05}\\\\
\end{array}$$

 

$${\frac{{ln}{\left({\mathtt{2}}\right)}}{{\mathtt{0.05}}}} = {\mathtt{13.862\: \!943\: \!611\: \!198\: \!906\: \!2}}$$

13.86 time units needed to double the investment.

Jul 13, 2014
 #15
avatar+11912 
0
Jul 13, 2014

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