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Well 2+2=4 just think of 1+1+1+1

To help out Love2Read...there is no y intercept for the last one

The y intercept would occur where x = 0

But letting x =0  means a negative under the radical which can't result in a real number  !!!

Starting at t= 0.5 it takes until 1.5 to get back to its resting position (1/2 of a cycle) =  1 sec

Let's write

y = 3^(x - 1)       take the log of both sides

log y = log 3^(x - 1)

log y = (x - 1)log 3

log y / log 3 = x - 1

 [ log y / log 3 ] + 1   = x            swap x and y

[ log x / log 3 ]   + 1   = y   =   the inverse

Hello there bro let me help you out,

 I will do a problem for ou so you can figure it out!

As we can see we have f(x)=1/2 square root x-3

first thing that we need to do is find the zeros, which ill give you a hint, we have only 1 and it is displayed in the question.

that answer is the x-3 but the zero isnt -3 because we have to flip the sign which gives you 3 as your zero

now for the y intercept it isnt as simple

In fact I couldnt really find a Y intercept myself so I would have to say that there is either no Y intercept or that the intercept is 0.5

First one :  Good job  !!!!!

Second

x^3 - 10x^2 + 24x

y intercept  - easy - let x = 0    so  y = 0

zeroes...... factor

x ( x^2 - 10x + 24) = 0

x (x - 12) ( x + 2)  = 0

Set each factor to 0 and solve for x and we get that    x = 0 , x = 12  and x = 2

(2x - 3) ( 3x + 2)  =

2x *3x  - 3*3x + 2*2x- 3*2  =

6x^2 - 9x + 4x - 6  =

6x^2 - 5x - 6

Easiest to  use exponential properties and then convert to radical form

 (x^4y^7)^2/3  =

[ x^4 ]^(2/3)  * [ y^7 ]^(2/3)  =

x^(8/ 3)  * y^(14/3)  =

x^( 2 + 2/3)  *  y^(4 + 2/3)  =

x^2 * y^4  * x^(2/3) * y^(2/3)   =

x^2 * y^4  ∛ [ x^2 * y^2 ]

You were correct   !!!!

So sorry for the late reply! Thank you again for the help!

5441 084843 431591 615659 571291 428668 923255 549962 214089 160997 541170 290830 516266 773395 936827 128499 431593 969046 448477 687463 427177 903244 520307 433540 723695 388709 656001
This number is simply powers of 3 numbers multiplied together as follows: 3^40 × 7^80 × 67^40

Merci i’ll try the next 10 problems on my own 

10(3+8k)+9(k+3)      =

10*3  + 10*8k  + 9k + 9*3  =

30 + 80k + 9k + 27  =

57 + 89k

De rien.....

without digging into it too deeply you look like you know what you're doing.

To be honest once out of college I never had to solve any analog circuits.

Merci bon monsieur

-4 ( 7r + 7)  =

-4* 7r    +     - 4 * 7   =

-28r    -  28

Yep, thanx !...I overlooked that....will edit.... 

17 + e^(7x) = 33     subtract 17 from both sides

e^(7x)  =  16           take the Ln of both sides

Ln e^(7x)  = Ln 16      and we can write

(7x) Ln e  = Ln 16         Ln e = 1.....so we  can ignore this

7x =  Ln 16         divide both sides by 7

x =  [ Ln 16 ]  / 7

AB = AC                                                        given

Angle 1 = Angle 2                                         given

Angle BAD is supplemental to Angle 1         supplementary pair

Angle CAD is supplemental to Angle 2         supplementary pair

Angle BAD  + Angle 1 = 180                         definition of supplemental

Angle CAD + Angle 2 = 180                          definition of supplemental

Angle BAD + Angle 1 = Angle CAD + Angle 2      substitution

Angle BAD = Angle CAD                                      subtraction property of equality

AD = AD                                                               reflexive property of equality

Triangle DAB congruent to Triangle DAC            SAS

Angle B  = Angle C                                            corresponding parts of congruent triangles are congruent

EP: Good Job!. A slight oversight. Plan 2 "accumulates 10% annual interest which compounds annually."

$10,000 x {1.10}^10 = $25,937.42.

You are correct, EP.....I didn't see that we had 5 people...!!!!

Hey Chris.....why would this NOT be  5 P 3 = 60

  which would include the outcomes quoted in the question?

Any 3 can finish 1st

And, after this, any 2 can finish second

So

3 x 2   =   6  possible finishing orders

4 (10)^(5x) = 200       divide both sides by 4

(10)^(5x) = 50          take the log of both sides

log 10^(5x) = log 50       and by a log property, we can write

(5x) log 10  =  log 50        log 10  = 1  ....so we can ignore this.....and we have

5x  =  log 50             divide both sides by 5

x =  [ log 50 ] / 5