for the first question, you take out a \(25x^2y^6\) and take the square root, so you get \(5xy^3\), and then you still have a \(3x\) still in there, so first one's answer is
\(\boxed{5xy^3\sqrt{3x}}\).
for 2nd question, subtract 2 from both sides, then square, to get \(2x-1=x^2-4x+4\).
now take away \(2x-1\) from both sides, to get \(x^2-6x+3\). now use quadratic formula, \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\), and plug in the values to get \(x = {-(-6) \pm \sqrt{(-6)^2-(4)(1)(3)} \over 2}\). im gonna let you do the rest, just for a tiny exercise 
for 3rd one, every solution will make one of those terms 0, so the answers are \({1 \over 2}, 8, \) and \(-1\).
the last one, plug everything in to get \(4^4-2(4)^3+5(4)^2-20(4)-4\).
and that is your second little exercise 
HOPE THIS HELPED!
