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You know how to do it but you want to see if anyone else does?

So when no one bothers with it you can bask in the illusion of your supremacy?

Here's an idea... p i s s off.

4L + 2S =2L + 6S, solve for L
L = 2S - This means the capacity of 1 large pump = 2 small pumps.
4L + 2S = Equivalent to 5 Large pumps in capacity.
8 Large pumps + 8 Small pumps = Equivalent in Capacity to 8+4 = 12 Large pumps.
12 large pumps / 5 Large pumps = 2 2/5 times - filling capacity of 8 Large and 8 small pumps.
Therefore it takes: 120 minutes / (12/5) =50 - minutes to fill the pool.
50/2 =25 minutes to fill 50% of the pool.

are you the rude guest? lol no offense if u arent but if you are you should know what im talking about

this means that either x-64, x^2-64, or x^3-64 is 0. so x can be 64, 8, -8, or 4 for a total of 4 solutions.

First find each day's ratio...

Mon.

15:7

Tues.

18:9

Wed.

14:14

Thurs.

15:6

Fri.

9:19

Now simplify each

Mon.

15:7

Tues.

1:2

Wed.

1:1

Thurs.

5:2

Fri.

9:19

 Then you can tell it is Thursday.

how much work do emma and carolyn accomplish carring the balloons up to the roof?

P.E. = mgh    m= mass  g = gravity (9.8 m/s^2)     h = height (meters)

      =  (8.16 kg) ( 9.8 m/s^2) (28.3 m ) =   .............     j         I think you can do the multiplication !   

x=small pump rate    y = large pump rate

4y + 2x  = Swimming pool (in 2 hours)    = 1 pool/2hr

AND:

2 y + 6x  = swimming pool  (in 2 hours) = 1 pool/2hr

From the first equation    2x = 1/2 - 4y

                                          x = 1/4-2y     substitute this into the second equation

2y + 6 ((1/4-2y) = 1/2   Solve for y

2y + 6/4 -12y = 1/2

-10y = -1

     y = 1/10 pool/ hr       Sub this into 1st(or 2nd) equation:

                             4(1/10) + 2x = 1/2          solve for x = 1/20 pool/hr

Now    :    for the final part of the question.....

                 ( 8(y) + 8(x)) t = 1/2 pool

                 ( 8(1/10) + 8(1/20) ) t = 1/2

                    (16/20 + 8/20) t = 1/2

                      (    24/20 ) t = 1/2

                         t = 1/2 * 20/24 = 20/48 hr    =    20/48*60 = 25 mins     

in each day, you take the ratio of blue to green, and find the highest. or, by careful eyeballing, you can deduce that the answer is Thursday.

24 minutes

This question has been posted like 4 times in the last week or so.....

Thanks

I think the function might be

y =15 cos [ (2pi/365) t ] + 43

The water level is at a max at day 0  =  58 cm

The water level is at 30 cm about 153 days after this

I used x for t   here :

oh okay thanks!

Thanks, HMB.....!!!!

it is the one highlighted in red at the bottom on @cphill 's answer 

What is a cosine function that represents the graph??

You are close...HMB....!!!

The equation of the midline is  y = - 3

3.  The equation is

y = 2cos (2x) - 3

the period is 3.14 (the distance from one peak to the next)

the amplitude would be 2 as it is the distance between the centre point and peak

the frequency is 1/3.14 

the equation of the midline of the function would be x=-3

ignore if blatantly wrong  haha

All we can do is to solve for x

y = 4 + 2x

 y - 4 = 2x

[ y - 4 ] / 2   =  x

A.  The radius can be found as 

[ highest point - lowest point ] / 2  = [55 - 5 ] / 2   =  50 / 2   =   25  yd

So A is true

B.  False....the lowest point is at 9 seconds

C. False....max height = 55 yd

D True

We have the form

f(x) = A sin (Bx) +  D

A = the amplitude =  [ highest point - lowest point] / 2 =  [ 10.2 - .1] / 2 = 10.1/2 = 5.05

The period is 24

B = 2pi / period =  2pi /24  =  pi/12

D = the midline =  (highest point + lowest point] ) / 2  =  (10.2 + 0.1) / 2 = 10.3 /2 = 5.15

So....the equation is

f(x) = 5.05sin [ (pi/12) x ] + 5.15

\(Carystax = (43000-11000)(0.2) +(45600-43000)(0.4) = 7440.00L\)

\(Megantax = (43000-11000)(0.2) + (150000-43000)(0.4) + (158900-150000)(0.45) = 53205.00L\)

sorry couldn't get pounds sterling sign to work

The graph is horizontally compressed by a factor of 2 and shifted up 1 unit

OK....I'll post a pic