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I got it, thanks

Cool. I watched it, but I still don’t even know how to do this.

This shoud be helpful I think

Nickolas, this is way over your head :)

Dah, a circle is actually a special case of an ellipse.

A circle is an ellipse where for foci are the same point.

πr(g+r), where r is the radius of the base and g is the slant height. 

Hope this helps!

( 0,1173 kg . 2,2 . 103 J kg-1 K-1 . -31°C ) + ( 0,1173 kg . 4,18 . 103 J kg-1 K-1 . 87°C ) + ( 0,1173 kg . 4,18 . 103 J kg-1 K-1 ) = smeltwarmte smeltwarmte=J kg-1 = rs

What are the units of the   2.2    4.18  ?      Also, it appears you need to convert the C degrees to Kelvin.

In a certain hyperbola, the center is at (2, 0), one focus is at (2, 6)  and one vertex is at (2, -3). The equation of this hyperbola can be written as

\(\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1 \)

Find h+k+a+b

Try looking at this:  

I need d in the second focus of the ellipse

He can't access google docs? But yeah you should be able to use Word, just going through the same process.

I like LagTho's  addition too about the tringle being upside down  :)

No, like the oval shape

I can't get enough from the description. Copy the picture into google docs, then go into file. Download as PDF, then click the up arrow on the pop up on the bottom left part of your screen. Give it a unique name, making sure you keep the .pdf, and download it to your desktop. Then go to upload the image, and click choose file. Type in the name you gave it, and then you can upload it.