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Aug 3, 2014
 #2
avatar+3502 
+3
Aug 3, 2014
 #1
avatar+3502 
+8
Aug 3, 2014
 #6
avatar+11912 
+3
Aug 3, 2014
 #8
avatar+33661 
+5

Stu, if you use the results I provided here: http://web2.0calc.com/questions/inverse-matrices_1 you should be able to calculate the inverse ok.

However, I don't think you should expect better marks for solving it as a 3x3 rather than as a 2x2 plus a substitution.  The latter is easier and I'm a great believer in the KISS principle (Keep It Simple Stupid!  Or in your case, perhaps: Keep ISimple Stu!) 

Aug 3, 2014
 #4
avatar+1832 
+3
Aug 3, 2014

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