All Answers 356000 Answers

Maybe a moderator has not seen them.

Or maybe the moderator thought that the answer was very obviously inadequate.

Many questions have answers and are not ticked, why is that?

The tick just means that there is an answer.

It is not an indication of correctness of that answer.

If the asker of the question (or anyone else i suppose) is not happy then it is up to them to say something.

The question can be unticked, if there is a polite request with a reason.

Yep!!!

Who ticked this?

Her  route forms  a   3 - 4 - 5 right triangle

The perimeter  =  the total distance she walks =  12  (miles)

So

Distance Walked 

_______________   =    Time

 Rate  Walked

Can you  solve this, macabre  ???

Evaluate

arcsin  (20/25)

Make sure your calculator is in DEGREE mode....

c   <  d

Since  a  is positive, then  1/a  is also positive

Add  1/a  to  both sides

c + 1/a  <  d  + 1/a

The equation MATH = COU + NTS can be made true if each of the letters M, A, T, H, C, O, U, N and S is replaced by a different digit and the equation is seen as the sum of two three-digit integers resulting in a four-digit integer.
If C = 2, a solution can be found in which one of the three-digit integers is a multiple of 23.
In that case, what four-digit integer does MATH represent?

MATH = COU + NTS

  1034 = 298 + 736         736 is a multiple of 23.

% increase   =

[ New Value  - Old Value ]

______________________   x   100%   =

      Old Value

[6000 - 5000]

___________  x  100%      =

    5000 

1000

____    X  100%

5000

1

__   x  100%      =     20%

 5

3x^2 + 4x  - 8  = 0

Use the quad formula  with   a  = 3   b = 4  and c  =  -8

So  we have that

                -4 ±√ [ 4^2 - (4 * 3 *  -8) ]            -4 ±√[16 + 96]            -4 ± 4√ [ 1 + 6]

 x =          _____________________   =    _____________  =    ____________ =

                             2 * 3                                        6                             6

- 2 ± 2√7

________  =    "C"

      3

45.8366236105

it's D ?

Yep, no disagreement here.   

That icon was DS.....yep....I think he "borrowed" my icon for a bit....LOL!!!!

You were definitely the "red dino,"  Melody.......!!!!

So many people who have come and gone......good memories  ( of most of them )

Define \(f(x)=3x-8\).

If \(f^{-1} \)is the inverse of \(f\), find the value(s) of \(x\) for which \(f(x)=f^{-1}(x)\).

\(\begin{array}{|rcll|} \hline \mathbf{f(x)}&=& \mathbf{3x-8} \\\\ x &=& 3 f^{-1}(x)-8 \quad & | \quad \mathbf{f^{-1}(x)=f(x)} \\ x &=& 3 f(x)-8 \quad & | \quad \mathbf{f(x)=3x-8} \\ x &=& 3 (3x-8)-8 \\ x &=& 9x-24-8 \\ 8x &=& 32 \\ x &=& \dfrac{32}{8} \\ \mathbf{ x } &=& \mathbf{4} \\ \hline \end{array} \)

Given f(x)=5x+2 and g(x)=3x^2-4x, evaluate f(f(1))-g(g(2)).

f(1)  =  5(1) + 2  = 7

So ....   f (f(1))  = f(7)   = 5(7) + 2  = 37

g(2)  =   3(2)^2 - 4(2)  =  4

So  ....    g(g(2) )  =  g(4)  =  3(4)^2 - 4(4)  =  32

So

f(f(1))  - g (g (2) )  =

37  -  32   =

5

Your research skills are very good CalculatorUser.   I am very impressed  

The guy in the space suit, that was DragonSlayer I think.

Didn't DragonSlayer take your icon for a while Chris.  He wanted it and you said that was ok.  Later he gave it back again.

Yes, i was a red dinosaur for quite a long time. I also had a design that another member made for me for a while. 

Rosala had that 'girl' pic for a long time.  I like it!

I had this one for a long time.

this was definitely in the 'Zegroes and Rosala' era.  Around 2014 I think.

I was never qutie sure if I was the girl or the dinasaur although Zegroes had no such confusion.   LOL

When I first joined the forum (28th Sept 2013 ) it was completely different.  There were not even any moderators, or the ability to have any moderators. It was nothing more than a list of posts. Some were mathematical but they rarely recieved any answer. There was no Latex, it did not look very mathematical, and it was almost empty, just a few kids used it as a secret chat site.  Ahr, the memories  

Thank you, asinus !

GCD [ 60786078, 25632563, 12345123, 41879187] = 1

2 * ( 2*pi * r)   =  pi * r^2       divide through by pi

2 * 2 * r  = r^2

4 r   =  r^2       rearrange as

r^2  - 4r   =  0       factor

r ( r - 4) = 0

Set each factor to 0  and solve for r and we get that

r  =  0   inches    (reject)

r  = 4 inches       (accept)

My web excavating skills have dug me to the very bottom of the deep web!

Ok maybe I will avoid the dark web

AHHHHHH!!!!

How could I forget  ???

This one was due to   Zegroes  ( and old member, sadly gone)  calling Melody and I "dinosaurs".....

I think she had another "dino" pic, too.....

I just found it lol

I remember this one.....I thought she also had another when I first joined the site, but I can't remember what it was ........(maybe I'm dreaming....LOL!!! )