@@ End of Day Wrap : Tues 12/8/14 Sydney, Australia Time 10:05pm (Really Wed morning) ♬
Hi all,
It's aleady getting busier I think. Our fabulous answers were today provided by NinjaDevo, CPhill, Alan, AzizHusain, TakahiroMaeda, DragonSlayer554, admin, Will85237 and Rosala. Thanks ![]()
Our King is still deciding upon the 'look' for his (and ours) Kingdom of Camelot. The score board has changed a couple of times again today. Nothing is final yet. ![]()
Here are some interest posts for today:
Rosala's Laughs
http://web2.0calc.com/questions/lets-end-the-day-with-a-laugh_8
*Finding Complex Roots (Ninja, this is an Extension Senior Topic - Imaginary numbers) ![]()
http://web2.0calc.com/questions/how-do-i-solve-the-sqrt4-16-complex-numbers-4-different-roots
Bearings always cause a bit of a problem.
I hope that everyone who is back at school today is finding it fun and interesting. ![]()
That is it for this evening. Good night.
♫♪ ♪ ♫ ♬ ♬ MELODY ♬ ♬ ♫♪ ♪ ♫
I just did a page of LaTex for this (which I lost) and I am not going to repeat it BUT
Here is a page that I put together on negative indices. It should help you understand how it works.
http://web2.0calc.com/questions/indices-especially-negative-indices
Very simplistically,
If something is raised to a negative indice you swap it to the other side of the fraction line and change the negative index to a positive index.
Also do you mean
2x/3(y^-1) which means $$\frac{2x}{3}\times y^{-1}$$
or do you mean
2x/(3(y^-1)) which means $$\frac{2x}{3y^{-1}}$$
You need to learn to use brackets so that your meaning is unmistakable!