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This thing (the problem lol) is an arithmetic progression.

there's a formula for this type of problem.

Let's say A is the first term and A_n is the last term, and d is how much each number is increasing from the last. so first we should first find the number of terms in the progression. the equation is:

A_n = a+(n-1)d

so ya plug in the values:

99=1+(n-1)2

98=(n-1)2

n-1=49

And n=50

There are 50 terms in all…

Now the sum of these fifty terms:

S_n = n/2(A+A_n)

S₅₀=25(1+99)

Sooooo the answer is 25*100 = 2500

b + c = 4 + (-7) = -3.

The number of possible vote totals is 50*49*48*47 = 5,527,200.

First, we should prime factorize all the numbers:

21 = 3x7

35 = 5x7

60 = 3x4x5

The GCD is just the product of all the factors that all three of the numbers share. Since there's no common factor for all three of them, the answer is 1. (because the 1 is a common divisor for all real numbers) 

:)

The sum adds up to 707,285,522,570 = C(57,12), so (n,k) = (57,12).

hmmm the answer is actually \((-1,1]\)

thanks for trying to help though

The matrix A is

\(\begin{pmatrix} 4 & 7 & -1 \\ 7 & -1 & 4 \\ -1 & 4 & 7 \end{pmatrix}\)

(1) There are 6*16 = 96 ways of choosing the diagaonals.

(2) There are 422 ways of choosing the senators.

(3) There are 8*9*8 = 288 ways of seating the knights.

(4) The probability is 3/5.

Hope this helps!

This may help you a bit 

A = (LX * XY) / 2 = 16

he can just make another account lmao

Ah okay then.

Let WXYZ be a trapezoid with bases XY and WZ. In this trapezoid, ZXW=105 degrees, XWZ=43 degrees, and XYZ=141 degrees. Find YXZ, in degrees.

Angle YXZ = 32 degrees  

(a+b)/2 is the average of a and b, thus it is in the middle of A and B, so the distances are equal.

No problem.

Thanks for some guidance. I do have some of this problem done but I'm just stuck right now. Hopefully this will help. Also, then wouldn't triangle ACE be similar to EBA?

Also, I'm seeing a lot more relationships between the angles now that you gave me a hint. 

Tan 60 = opp/ adj = 3150/d      d= 1818.65

tan 30 = opp/ adj = height / 1818.65      Height of second plane = 1050 meters

now you can find the distance between the two planes because you have both of their altitudes.....

If 6 is a root , when you put in x= 6 the eq should = 0

6²-2(6) +a = 0

36-12+a = 0

a = - 24

Formula for the n^th term of an arithmetic progression:  t_n  =  t₁ + (n - 1)d

--->   389  =  t₁ + (30 - 1)d   --->   389  =  t₁ + 29d

--->   181  =  t₁ + (14 - 1)d   --->   181  =  t₁ + 13d

Subtracting:                                  208  =  16d

                                                        13  =  d

To find the first term:     181  =  t₁ + 13d   --->   181  =  t₁ + 13(13)

                                                                          181  =  t₁ + 169

                                                                            12  =  t₁

Now, you know that  t₁ = 12  and  d = 13,

use this formula to find the 25^th term:   t_n  =  t₁ + (n - 1)d

And use this formula to find the sum of the first 25 terms:  Sum  =  n( t₁ + t_n ) / 2

where  n  is the number of terms

          t₁  is the value of the first term

          t_n  is the value of the last term.