Probably temporary I want to get back to if possible. 30/8/14
Physics:
http://web2.0calc.com/questions/physics_65
modular Arithmetic:
http://web2.0calc.com/questions/443-443-what-are-the-last-three-digits
Good fluid solution question (thanks Chris and Alan)
More to look at here Heureka's given a web address
http://web2.0calc.com/questions/trigonometry_78
Physics - I do wish I understood more Physics. 1/9/14
http://web2.0calc.com/questions/i-need-to-understand-these-questions-in-details
http://web2.0calc.com/questions/check-my-answers
I really look at these CALCULUS tutorials that Chris keeps suggesting.
http://web2.0calc.com/questions/as-limits-approach-infinity#r2
25.04*3.005
the first one has 2 dp the second has 3 decimal places so the answer will have 5 decimal places
Now multiply ignoring the decimal places.
If you do not know how to do this look here
http://www.mathsisfun.com/numbers/multiplication-long.html
2504 * 3005
I will do it one the site calc.
$${\mathtt{2\,504}}{\mathtt{\,\times\,}}{\mathtt{3\,005}} = {\mathtt{7\,524\,520}}$$
we need the 5 decimal places (5 numbers after the point)
75.24520
We do not need the last 0 so the answer is
75.2452