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Thanks for showing me that.

Your souce is right.

I have double counted.

For the last 3 cards I have counted  order where I should not have.

I mean I have counted 345 separately from 354 etc.  where they are both the same.

I could have fixed this by dividing my answer by 3! = 6

6 300 000/6 = 1050000      And now the answers are the same    

ok, I did not think about the question properly.

let alpha be a very small positive number

if x=1+alpha  then  1/(x-1)  is a positive huge number.

tan of a positive huge number 

if x=1-alpha  then 1/(x-1)  is a negative equally huge number.

tan of a positive huge number is not equal to tan of a negative equally huge number.

So yes I suppose it is reasonable to conclude that the function is not continuous at x=1.

I don't get your explanation and the answer is incorrect...

At the very least, a minimum of 32 different solutions to the exact value of 24 pts

Have you tried to graph it out before you came here? ಠಿヮಠ

What is the value of x^2 + y^2?  

Draw the diagonal of the square that connects the end points of  x and y. 

The line you just drew serves as three components we're interested in. 

It's the diagonal of the square. 

It's the diameter of the circle. 

It's the hypotenuse of a right triangle. 

Since it's the hypotenuse, its square is equal to the sum of the squares of the other two sides. 

The square of the hypotenuse is 10² = 100.  

Therefore x² + y² = 100  

_.

can you explain why it may be C ?

the first says it is c, im confused:/

the other one makes sense! i forgot about that

I am posting this on behalf of Nacirema.  I have not tried it myself.

Copied from a private message:

"Sorry, it will not let me post. Can you post this on my behalf please:"

I have a fairly nifty trick which I use to upload the screenshots when the image file does not pull up. In fact, this works with almost any image I try to upload to https://web2.0calc.com! Please read to the end, I do not want you to do it the hard way.

Step 1: Create a second email. 

Step 2: Go to http://hangouts.google.com.              I know this sounds irrelevant, but trust me it works. 

Step 3: Feed in the email address to the (+Add Contact) option. 

Step 4: Go to http://hangouts.google.com on the new email address.

Step 5: Go to invites and accept the invitation.

Step 6: Upload the image that you want to paste onto http://web2.0calc.com.

Step 7: Once it has sent, click on the image. It will open a new tab.

Step 8: Copy the URL Code and come back here. 

Step 9: Click on the image option and paste the URL Code into the URL Code slot. It ought to have uploaded by this time. You are done. Once this is done, and each time you want to upload a new image, repeat from Step 6, not Step 1. This saves significant time.

Nacirema

I do not think the first one can be determined using limits.  (It is undefined)

the second one is very straight forward  it is just e^0 and that has the defined value of 1.

any number to the power of 0 is 1

 e is just a special irrational number. Its value is approx 2.718

how would i round 278414359.311 up to 3 significant figures? i dont understand...would it just be 278?

Hi Nirvana!

You write after the three significant digits  \(278\times 10^n\)
n is the number of digits between the third number 8 and the point, i.e. 6.

Round 278414359.311 up to 3 significant figures.

\(278414359.311\approx 278\times 10^6\)

greeting

  !

Draw a Venn diagram to visualize this more easily:

yes     278 with a 000 000   after it   

∠RTU + ∠STR = ∠STU

11x - 7 + 2x + 16 = 152

13x = 143

x = 11

Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).

Hello Guest!

\(x_P=x_A+\frac{2}{3}(x_B-x_A)\\ x_P=-2+\frac{2}{3}(3-(-2))\)

\(x_P=1.\overline{3}\)

\(y_P=y_A+\frac{2}{3}(y_B-y_A)\\ y_P=1+\frac{2}{3}(4-1)\)

\(y_P=3\)

The coordinates of point P are \(P\ (1.\overline{3},3)\)

  !

ilorty, 

Some of your links do not work at all and one goes to the wrong place. (For me anyway)

You need to check them.  

very true, the first looks like both , however i think its infinite in this case.

I like to get a second opinion just to make sure, sorry if I got to repetitive on asking. thank you for showing me how I can!

Simplify (2x + 5)/(x^2 - 3x) - (3x + 5)/(x^3 - 9x) - (x + 1)/(x^2 - 9)

What is the difference?

Hello Gast!

\( \frac{2x+5}{x^2-3x}-\frac{3x+5}{x^3-9x}-\frac{x+1}{x^2-9} \\ =\frac{2x+5}{x(x-3)}-\frac{3x+5}{x(x-3)(x+3) }-\frac{x+1}{(x-3)(x+3)}\\ =\frac{(2x+5)(x+3)-(3x+5)-x(x+1)}{x(x-3)(x+3) }\\ =\frac{2x^2+6x+5x+15-3x-5-x^2-x}{x(x-3)(x+3)}\)

\(=\frac{x^2+7x+10}{x(x-3)(x+3)}\\ =\frac{(x+5)\cdot (x+2)}{x(x-3)(x+3)}\\\)

\(\frac{2x+5}{x^2-3x}-\frac{3x+5}{x^3-9x}-\frac{x+1}{x^2-9}=\color{blue}\frac{(x+5)\cdot (x+2)}{x^3-9x}\)

  !

Thanks ilorty.

I think your knew news posts will be excellent.

Maybe we will all learn to spell too  

September 3, 2020:

Good evening! (or whatever time of day it is, good night just did not sound appropriate)

I try to post at 12 AM (midnight) GMT (8 PM where I am from), but not always on the dot.

Thank you EP for creating the most answers!

Let's start at     2  * 3 * 4 * 5 = 120     120 will not work.....but if divided by 5 and 1 is left...how about 121

then if divided by 5     one is left

   same with 4     and   3    and 2

so 121 camels would work the parameters given  BUT the question states it is LESS than 100

     let's back up by 25     to     96     won't work...back up 5 more

          91    works

A  B   or C

"complete the square' for    x   y  and z

x^2-4x               +       y^2+8y         +   z^2 +6z          =  4

(x-2)^2             +         (y+4)^2        +   (z+3)^2           = 4   + 4   + 16    + 9

center is thus     2, -4, -3           radius = sqrt (4+4+16+9) = sqrt 33  

line through (1,4) and (3,-2).....      slope  =  m =  (4- -2) / ( 1-3) =  -3

    perpindicular is  - 1/m  =   1/3

Point slope form of line thru   3, -5     with slope 1/3

(y+5) = 1/3 (x-3)