The composite figure is made of a rectangular prism and half of a cylinder.
prism volume = 5 * 11 * 6 = 330 mm^3
half cylinder volume = 1/2 * pi * (5/2)^2 * 11 = 34.375pi mm^3 = 108 mm^3
Total: 330 + 108 = 438 mm^3
The probability is 2/5.
I hate to say this, but this question is quite unnecessary and takes up space (so that other peoples' questions may not get covered). Please refrain from posting these kinds of questions if you already know the answer.
Technically, there are infinite answers, but the number that is in the middle of 0 and 1 is, $\frac12$
Sorry, I meant 41, not 47.
I believe you've posted this questions already: https://web2.0calc.com/questions/whattt_6
The answer would be 41.
Hope this helped!
Caffeine :)
If it is prime, that means that last number has to be odd. this leaves us with 5 digits for the last one: 1,3,5,7, and 9. but becayse the digit in the units place is 3 less than the digit in the tens place that has to be 3,4, or 5, we have only 1 answer: $\boxed{41}$
we can first calculate the rectangle beneath the smicircle's area, which is 20x25=500
we see that the radius of the semicricle is 12.5, and the area of the circle is $\pi$r$^2$, so the area of the semicircle is:
$\frac{\pi r^2}{2}=\frac{3.14\cdot156.25}2=245.3125$
500+245.3125=745.3125
It is most likely the 4th one.
We know that in a 30-60-90 triangle, the length of the hypotenuse is 2x where the length of the side opposite of the 30 degree angle is x, and the length of the side opposite of the 60 degree angle is x*sqrt(3).
Knowing this, x in our case would be 6, so the side opposite of the 60 degree angle would be 6√3 inches, or 10.39230484...
Caffeine
We can use trigonometry for this problem. This would give us:
(tan)42 = x/18
(tan)42*18 = x
16.2 = x.
So the flagpole is around 16.2 meters.
Let's see, some options we have are:
31, 37, 41, 43, 47, 53, and 59.
So our answer must be 47 as the digit in the one's place (4) is three less than the digit in the ten's place (7).
Terribly sorry, I found several wonderful answers here: https://web2.0calc.com/questions/need-help-please_46
(if anyone wants to see as well).
There are 540 ways of coloring the diagonals.
Notice that \(83^9 + 1\) and \(83^9 + 83^2 + 1\) differ by \(83^2\). Therefore, if they have a common divisor, then that divisor must also be a divisor of \(83^2\). (To see why this is true, suppose \(d\) is a divisor of \(83^9 + 1\), so that \(83^9 + 1 = dm\) for some integer \(m\); also suppose that \(d\) is a divisor of \(83^9 + 83^2 + 1\), so that \(83^9 + 83^2 + 1 = dn\) for some integer \(n\). Then \(83^2 = d(n-m)\).) Since 83 is prime, the only (positive) divisors of \(83^1\)are 1, 83, and \(83^2\)itself. But 83 cannot be a divisor of \(83^9 + 1\) (which is clearly 1 more than a multiple of 8). Therefore, \(gcd(83^9 + 1, 83^9 + 83^2 + 1) = \boxed{1} \).
$83^9+1$ is 186,940,255,267,540,404.
$83^9+83^2+1$ is 186,940,255,267,547,293
The GCD is 1.
https://www.calculatorsoup.com/calculators/math/gcf-euclids-algorithm.php?input1=186940255267547293&input2=186940255267540404&action=solve
Thanks, but none of those are correct
In first row, no. of color permutations = 3!
= 6
similarly for the next 2 rows = 2 * 6
= 12
Thus, total no. of ways are 12.
Here you go :-
2y = 8x - 6
⇒y = 4x - 3
⇒\({dy \over dx} = 4\)
Slope of perpendicular line = -1/4
Hence, equation of line
\(y - 3 = ({-1\over 4})({x - (-3)})\)
\(4y - 12 = -x - 3\)
⇒\(x + 4y = 9 \)
a) Coordinate points are (2015,4023) and (2018,3711).
b) Difference = 4023 - 3711
= 312
Rate of change = \({312 \over 4023}* 100\)
= 7.76%
Since AD and AB are equivalent, assuming line AC passes straight through the kite in half, angle 1 would be 25o.
Following, angle 3 has to be 65 because the total angles in a triangle are 180, and we already know two of the angles (25 and 90) 180 - 90 - 25 = 65. This means your answer is 25, 65. (the second one from the top)
we sum the two given angles, to get 36+113=149
360-149=211
we see that choice 3 and 4 don't work, because they don't sum to 200, and choice 2 doesnt work because the last digit will be 0, so choice 1 is our answer
a = 180 - 36
b = 180 - 113
\(\begin{align*} f(\sqrt[3]{-8})&=|\lfloor{-2}\rfloor|=2\\ f(-\pi)&=\lceil{-\pi}\rceil^2=-3^2=9\\ f(\sqrt{50})&=\lceil{\sqrt{50}}\rceil^2=8^2=64\\ f\left(\frac{9}{2}\right)&=|\lfloor{\frac{9}{2}}\rfloor|=4\\ 2+9+64+4&=\boxed{79}\\ \end{align*} \)
Its wrong
