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D, 

Notice  that  y changes  by 4  when x  changes  by 1

So....the slope of  this function  is  change in y  / change in x  =    4/1   = 4

Since  the  point  (-3, -16)  is on the  graph, we have

y = 4 ( x - - 3)  -  16

y = 4 ( x + 3)  -  16

y = 4x  + 12  - 16

y  = 4x  - 4

Yall should be my math teacher...

Area of WHOLE circle = pi r^2 =  16 pi

   shaded area is a fraction of 360      80 out of 360

         80/360   *  16 pi = .......... in²

PIck a pair     say   -7   -32      sub into first equation    -32 = -4(-7) - 4   ?  

                                                                                      -32 = 24 ?    no

try the next one      and the one after that  and the one after that until one of them is 'true '    <====== that will be your answer

y changes  by  1.5   when  x changes  by   3

So....the  slope of  this linear  finction is     1.5   / 3   =  1/2

Since   (2,6)  is on the  graph   we  have  this linear equation 

y= (1/2) (x - 2 )  +  6      simplify

y=  (1/2)x  - 1  +  6

y = (1/2) (x)  +  5

When y  = 0   we  have  that

0  = (1/2)x  + 5

-5  = (1/2)x

x = -5 / (1/2)  =  -5 * 2/1  =   -10      when y  =  0

If the lines are parallel the two angles are equal

19x -4       = 110

19x = 114

x = 114/19 = .............

pi x d x h =  48.412 in^2      PLUS two endcaps   2    *   pi r² =  8.309  

                      total 56.72 in²

will have more questions comin out..

ED = 22 i^2 =   -22

then   -22 ( 11-5i)

                    = -242 + 110 i

We just need  to make sure   that  x^2  + bx   + 18    does  not  =  0

In other words,  we  need to have  the  discriminant  of  this  function be <  0

So

b^2  - 4 (1) (18)  <  0

b^2   - 72  <  0

b^2  <  72

This will  be  true  for  the  integer values  on    [ -8, 8  ]  

So  b  =  8  is the largest integer value of  b that will  give us a domain of all reals

each THREE drop in 'x' drops y by 1.5

soooo

6/1.5 = 4        so we need to drop 4*3 = 12  from 2    to   -10

yes i have 2 tests and i already did 1 and im currently doing another one LOL, such a busy day...

We  must  have that

sqrt (x^2 - 16) + 3    ≥  0

All we  really  need to worry  about    is   that  x^2   -  16  ≥  0

This will  be  true  on  two  intervals

(-inf , -4  ]   U  [ 4 , inf)     = the domain

See the graph here  ;   https://www.desmos.com/calculator/htuz2jh2j9

(4 - 5i )  ( 5 + 5i)   =

4*5 + 4*5i   -  5i * 5   - 5i * 5i   =

20  + 20i  - 25i   -  25i^2   =

20   - 5i  -  25 (-1)   =

20  - 5i  +  25   =

45  - 5i

f(x)  =  - sqrt ( -10x^2  - 4x  + 6)

We must  have  that

-10x^2  - 4x + 6  ≥  0                multiply through  by  -1  and reverse the inequality sign

10x^2  + 4x  - 6   ≤  0                   factor as

(10x  - 6) ( x + 1)     ≤  0          (1)

10x  - 6  =  0                        x + 1   = 0

10x  = 6                               x  =  -1

x =  6/10  =  3/5

We  have  three intervals to consider    (-inf, -1] , [ -1, 3/5 ]  , [ 3/5, +inf )

The midle  interval is the one that  makes  (1)  true

So.....the domain is   [ -1, 3/5 ]

See the graph here :  https://www.desmos.com/calculator/xwiv35snre

The value of a is 2.

The axis of symmetry is x = 4.

g(x) is defined for -1 <= x <= 3, so the width of the interval is 4.

Note  that the function  is NOT defined at x  = 0

When x  is  a large negative, f(x)  =  is only slightly  negative, but not  0

When  x is a very small negative,  f(x) is an extremely LARGE negative  verging towards  - inf

When  x is a small positive, f(x)  is a LARGE positive verging towards + inf

When x  is  a large positive, f(x) is only slightly positive, but  not  0

So....the  range  is   (-inf , 0)  U (0 , + inf)

The graph here confirms this  :  https://www.desmos.com/calculator/fmxqof7zjz

The sum of all solutions is 3/4.

The maximum number of jerseys is 25.

We  must  have  that

-6x^2 + 25x  - 4   ≥  0        multiply through by  -1, reverse the inequality sign

6x^2  - 25x   + 4  ≤  0           factor as

(6x  - 1) ( x - 4) ≤  0

6x - 1  = 0              x  -4  = 0

6x  =1                    x = 4

x= 1/6

Note  that  we  have  three intervals to consider  (-inf, 1/6]  , [ 1/6 , 4]   , [4, inf)

The one  that is good is   [ 1/6, 4 ]  =  the domain

See the graph, here  : https://www.desmos.com/calculator/r6wnwsrerf

It is all x   EXCEPT values of x that make the denominator = 0

denominator factors to

(x  -1)(x -6)     so x cannot = 1 or 6

*** edit ****     denominator cannot be negative either   ( no neg sqrt )    which is from 1 to 6

(-∞,1)  U (6, +∞)

I assume  that  this  might be

f(x)  = 151 + 4e^(-.2x)    if  so

Let  x  = 0

Then the y intercept is

y  = 151 + 4e^0  =    151  + 4 *1  =    155