All Answers 356371 Answers

= sqrt ( 60 * 12 * 63* 42 * x⁴)

= x² sqrt(190512)

=x² 252 sqrt(30)

g(x) would have to be of degree 8 for the sum of the two to be degree 8   ( since f(x) is only degree 5)

The area would be TWO complete circles' area + the area of the square

   cirlcel area = pi (d/2)^2               square area = side * side

 You should be able to take it from here .......

r=\(\frac2{2\pi}=\frac1\pi\)

c=r^2=\(\frac1{\pi^2}\)

c/2=\(\frac1{2\pi^2}\)

oops your grammer was wrong so i got confused just multiply by 4 and you get \(\frac2{\pi^2}\)

The probability is 19/100.

The distance is 2*sqrt(7).

h = 2/5 p     This is given

then

h = (p-20) * 2      sub in the red equation

2/5 p  = 2p -40

-8/5 p = -40

p = 40 * 5/8 = 25   origianlly had paul

P, 2/5P

2/5p = 2(p - 20)

2p = 10p - 200

p = 25

Thanks for you help Electric

(1 - 3/4 - 4/7 ) x = 9

There is a mistake in this question     3/4 + 4/7 = ( 21+ 16)/ 28 = 37/28     which is greater than one...cannot be.

You are given   d=60     find   s   by using the equation

But I think there is a typo in your equation...I will answer with an = rather than a minus sign

60 = - .0065 s^2  + .14s

0 = - .0065 s^2 + .14s -60    Use quadratic formula to find   s = imaginary numbers

                something is wrong with your equation as you typed it.....   if I use d in km    I get 21.1kilometers/hr   which I think is incorrect too

Please proofread your question......  is 's' really km/hr  ?  Is  d really meters ?   Is the equation correct?

If the equation is     d = .0065s^2 + .14s      THEN I get   s = 85.9 kilometers /hr

For the 3rd one I got -11/15

The area of triangle OPQ is 6.

The greatest load I can be sure of is 1800 pounds.

No, this is impossible.

There are 7*6*5 = 210 possible triangles.

From x + 3y = -5, y = -x/3 - 5, so the slope of the line is -1/3. The slope of the new line is also -1/3, so y = -x/3 + B.  Pugging in x = 2 and y = -7, we get -7 = -2/3 + B, so B = -19/3.

Then the line is y = -x/3 - 19/3.  Then 3y = -x - 19, so 3y + x = -19.  We want the right-hand side to be 3, so we mutiply both sides by -3/19: -9/19*y - 3/19*x = 3.  Therefore, A + B = -9/19 - 3/19 = -12/19.

The quadratic is (x + 7)^2 - 4 = x^2 + 14x + 45, so b + c = 14 + 45 = 59.

There are 7 different possible products.

First ,   1 mm   does NOT equal 1 cc        1 ml   does equal 1 cc.

             one is a length....the other is a volume.

Second 

     Volume of funnel = 1/3 pi r^2 h

                                = 1/3 pi 4² 12 = 201  ml

    NET volume going into the cone is (I assume ml   NOT mm )    60-40  = 20 ml per second

              201 ml / 20 ml/sec = ~~ 10 seconds

If the diameter is 99, the radius is 99/2. 

The volume of a sphere is 4/3*pi*r^3

Don't forget to divide by 2 since you're looking for half of it.

=^._.^=

Vol  of  cube    = 20^3  =   8000 cm^3       (1)

Vol  of  sphere   =  (4/3) pi ( 10)^3   =   (4000/3 )  pi   cm^3        (2)

To  find  your  answer , subtract ( 2)  from (1)

Area  of  a  kite   =    (1/2)   product of  the  diagonal  lengths

So

60  =  (1/2) (20)  ( x)

60  =  10 x

60 / 10  =  x    =   6    =   the  length of  the other diagonal

Let S  = (0,0)

M  =   (0,2)

P  =  (2,2)

The  area  of  the  trapezoid   =   (1/2)MS  (MP + SR)   =  (1/2) (2) ( 2 + 3)  =  5

So....1/2   the  area  of  the  trapezoid  =    5/2

Which  means  that

(5/2) =(1/2) MS  ( MP  +  SQ)

5   =    MS  (MP  + SQ)

5  =   (2) (  2  +  SQ)

5  =   4  +  2SQ

5 - 4  =  2SQ

1  = 2SQ

SQ  =  1/2            so   Q  =  ( 1/2  , 0)

So   PQ    =   sqrt  [  ( 2 - 1/2)^2   + 2^2  ]    =   sqrt  [  (1.5)^2  +  4]  =  sqrt  [ 2.25 + 4 ]  =  sqrt 6.25  =  2.5   =

2  5/10    =      25 /10   =   5/2   = n/m

So  

m +  n   =    2  +  5    =   7