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https://web2.0calc.com/questions/plz-help-me-bxtch

Point P is at pi/4      everytime you add 2pi to this value, you will be back at point P

pi/4  + 2pi =  9pi/4

9 pi /4   + 2pi = 17pi/4         Cn you figure the next one?

2^2  *  3^3  * 4^4  *  5^5  *  6^6      =

2^2  *  3^3  *  (2^2)^4   *  5^5  *  2^6  * 3^6   =

2^2  *  3^3  *  2^8  *  5^5  *  2^6  * 3^6    =

2^16  *  3^9  *  5^5

We  need  3 *  5   =  15

when we expand (Ax+1)(Bx+5), we get -

ABx^2 + 5Ax + Bx + 5

we know that the coefficient of x^2 in the initial expression is 6, so therefore we know AB must be 6.

hope this helped! please correct me if i am wrong :)

y =  x^2  -  14x   -  21

x coordinate of the  vertex =  14/2  =  7

y coordinate of the  vertex  =    7^2  - 14 (7)  - 21    =  -70

Roots

x^2   - 14x   =   21      complete  the square  on  x

x^2   -  14x   +  49  =   21  +  49

(x - 7)^2  =   70

x - 7  =   ±  sqrt 70

x =  sqrt (70)  +  7

x =  -sqrt (70)  +  7

Distance  between  these points =    ( sqrt (70)  +  7 ) - ( -sqrt (70  + 7)  =   2sqrt (70)

Area of  triangle =    (1/2)  (2 sqrt (70)  )  (  70)  =   70*sqrt (70)  ≈  585.66

Consider  the  following

Find  the  area of  EFGH  =   EF  x  FG   =   5 x 4  =  20       (1)

Then

Areas of  right triangles  EBA, AHD , DGC   and  BFC  =

(1/2)  ( 1 * 3  +  4 * 1   + 1 *3   +  4 * 1)  =   

( 1/2)  ( 3 + 4  +  3 + 4)

(1/2) ( 14)   =  

7         (2)

Area of   ABCD   =   (1)  - (2)  =   20  - 7  =    13

I believe your question is not complete. Can you comment the complete question under my post so, I can answer it?

If i think about it, that should be right. but its not for some reason...

Here is a question that look similar

https://web2.0calc.com/questions/help-please-asap_31

I hope this helps!

Number of paths  ftom  (0, 0)  that  pass through  ( 4,3)  =

(R  R  R  R   U  U  U)  =   C( 7,4)  = C(7, 3)  =   35

Number of paths  from (0,0)  to  ( 5,7) =    

(R R R R R  U U U U U U U )  =   C(12, 5)  = C(12,7)  =  792

So....total  paths  from   (0, 0)  to (5,7)  that do not pass through  (4,3)  =  792   -  35  =    757

You can find the length of the sides sing the distance formula:

√((x2-x1)²+(y2-y1)²)

(x2, y2) is a coordinate point

(x1, y1) is a coordinate point

Once you find the two points you are going to use, plug them in into the distance formula and solve for the distance

Then, find the area

 If you don't understand this, check this out:

https://web2.0calc.com/questions/halp-plz_12

It's the same question

I hope this helped!

The fraction is 2/11.

Thank you!

B =  (3/4)D

After  Dan  received   $15   he  has    D  +  15

So

B  / ( D +  15)   =  6/11

(3/4)D  /  ( D + 15)  =  6 /11     cross-multiply

11 * ( 3/4)D  = 6 (D + 15)

(33/4)D    =  6D   +  90

(33/4)D  - 6D   =  90

(33/4)D   -  (24/4)D   =  90

(9/4)D  =  90

D  = (4/9) (90)  =     $40  = what Dan started with

Carl  must  have  started  with   $120

So

6 (120 -  S)   =  240

720  - 6S   =  240

720  - 240   =   6S

480  =  6S

480  / 6   =    80    ......Carl spent $80

x^2+10x+y^2+16y-k=0

x^2  +  10x   +  y^2   +  16y     =  k           complete the  square on x, y

x^2  + 10x  + 25    +  y^2  +  16y +  64   =  k + 25  +  64

(x  + 5)^2   +  ( y  + 8)^2   =   k  +  89

To  have  a circle with a radius of 6, the right  side needs to  be  36

So

k  +   89  =  36

k  =  36 - 89   =   -53

x, y   are  >   18

Let  z  = 18

Let  x  = z+ a

Let  b  =  z + b

So

1/ (z + a)  +  1 / (z + b)  =  1  / z

(z + b + z + a)  / [ (z + a) (z + b)  =   =  1/z

( 2z  + a +  b)  /  [ (z + a)  (z + b) ]  =   1  /z               cross-multiply

2z^2  +  az + bz   =   ( z + a)  ( z + b)

2z^2  + az + bz =  z^2  +  az + bz  +  ab              simplify

z^2  =   ab

18*2  =  ab

324  = ab

Factors of  324  = 

1 | 2 | 3 | 4 | 6 | 9 | 12 | 18 | 27 | 36 | 54 | 81 | 108 | 162 | 324 

ab  will be minimized  when   a = 12   and  b   = 27

So

x = a + z =   12 + 17 =   30

y =  b +  z =   27 + 18  =   45

Smallest possible value  for  x  +  y      =  30   +    45  =    75

Thank you

Call the  original price, P

So

P  ( 1 - .50) ( 1 - .25)  =   .75

P  (.50)  (.75)   =  .75               divide  both  sides  by .75

P (.50)    =  1

P   = 1 /  .50   =      2  ( dollars)

341

The solution is ... complicated

33 1/3% is equivlent to 1/3, 40% is 2/5, 75% is 3/4, and 50% is 1/2.  

Let's look at the top left black square, with the number in it equal to x.

Because the number above it is 1/3, we know that it is 1/3 of the column, so the white square below it is 2/3.  In this, we know that the bottom left white square is 2x.  

Moreover, because the bottom right black square is 25% of the bottom row, we have 2x as 75% of the bottom row.  

This means that the entire bottom row sums to 8/3x, and the black bottom square is 2/3x.  

With 2/3x being 50% of the right column, the white square is also 2/3x.  

Knowing this, we know that x is divisible by 3, and that 8/3x < 10.  This means that x must equal 3.  

However, plugging this value into the puzzle, we find that this is impossible.  Thus, there is no solution.  

Intuitively, we see that the top right square must be less than 5, meaning that the values are either 1, 2, 3, or 4 (or else the square under it will be greater than 10).  With each of these values, however, there is no solution.  

Very nice,  EL   !!!!!

Because we can factorize n^3+1, we simply write n^3+100 as n^3+1+99.  

Thus, because n+1 divides n^3+100, aka n^3+1+99, n+1 divides (n+1)(n^2-n+1)+99.  

Knowing that (n+1) will always divide (n+1)(n^2-n+1), we simply need n+1 to divide 99.  

The largest divisor of 99 is 99, meaning that n+1 will equal 99 to maximize n.  With this, we have n=98.  

The answer is 98.

Assuming linear.....or exponentiial rate?