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Thank you!

\(x = 180 - 90 - 52 = \color{brown}\boxed{38}\)

Each picture has area \(9 \times 12\). There are 11 of these, so the total area is \(108 \times 11 = \color{brown}\boxed{1,188}\)

Where is C located among the 8 vertices?

From my knowledge of geometry, I don't think a rectangle has 8 vertices......

Can you please rephrase your question

Thank you so much!

so the original cost was 349,900 how did you come up with those answers? 

its actually 349,900 ... I missed the 9 in 900 earlier which really threw me obviously

so do i subtract 34990 by .20 or multiply to get the down payment? 

The formula for diagonals is: \(s(s-3) \over2\)

We now have an equation to solve: \({s(s-3) \over 2} = 6s\)

Simplifying: \(s^2-3s=12s\)

Converting to a quadratic, we get: \(s^2 - 15s = 0\)

We know that \(15s = s^2\), so there are \(\color{brown}\boxed {15}\) sides. 

Write as a system of 3 equations: 

\(r = 8+i\)                       (1)

\(s = 4r\)                            (2)

\(i+r+s=96\)              (3)

Rearrange (1) so \(i\) is the independent variable: \(i = r - 8\)

Now, substitute i and s in terms of r: \(r + 4r + r-8 =96\)

Simplify: \(6r - 8 = 96\)

Add 8 to both sides: \(6r = 104\)

Divide by 6: \(r = 17 {1 \over 3}\)

Now substitute \(r\) into (1) and solve for \(i\): \(17 {1 \over3} = 8 + i\)

Subtract 8 from both sides: \(i = 9 {1 \over3}\)

Now substitute \(r\) into (2) and solve for \(s\): \(4 \times 17 {1 \over 3} = s\)

Simplify: \(s = 69 {1 \over 3}\)

The message wasn't directed to you, it was to catmg. 

You already said you were in 7th grade like me :)

uh... I only know sin, cos, and tan... I have no clue what sec and cosec are

Sorry lol!

Maybe someone else can help...