All Answers 356067 Answers

The area of a trapezoid is (base1+base2*height)/2

The two bases are 8 and 5

The height is 4

SO substituting these known values into our formula gives us:  ((8+5)(4))/2

((8+5)(4))/2 = 26

So the area of the trapezoid is 26 meters.

-Vinculum

"When recommending solutions to decrease human impact, which location were you able to make the greatest positive impact? Please explain your selection by using data from the simulation."

I am assuming this is probably Earth/Env Science...

Can you show a picture of the simulation so I can get a better understanding?

\(\frac{\left(-2x-12\right)}{2}>7\left(3-4x\right)\)

\(\mathrm{Multiply\:both\:sides\:by\:}2\)

\(\frac{-2x-12}{2}\cdot \:2>7\left(3-4x\right)\cdot \:2\)

\(-2x-12>14\left(3-4x\right)\)

\(-2x-12>42-56x\)

\(\mathrm{Add\:}12\mathrm{\:to\:both\:sides}\)

\(-2x-12+12>42-56x+12\)

\(Simplify\)

\(-2x>-56x+54\)

\(\mathrm{Add\:}56x\mathrm{\:to\:both\:sides}\)

\(-2x+56x>-56x+54+56x\)

\(Simplify \)

\(54x>54\)

\(\mathrm{Divide\:both\:sides\:by\:}54\)

\(\frac{54x}{54}>\frac{54}{54}\)

\(Simplify\)

\(x>1\)

-Vinculum

Hey Kakashi did you get it?

If not I can solve it.

What science is this, if it is something I have done before I can assist you..... :)

srry not an anwser but tht msge about telsa messed up the thing so u have to delete it for me to msge u bck

Thanks Kakahi,    

I just want to look for myself   

Given that m - 2 is a positive integer that divides 3m^2 - 2m + 11, find the sum of all such values of m.

f(m)=3m^2 - 2m + 11

f(2)=12-4+11 = 19    that is the remainder/

19 is prime

19/(m-2) must be a whole number

m-2=19    or m-2=1

m=21     or   m=3

Just like  Kakashi said :)   

your question does not make sense.

 What is the ratio of the area of triangle ADE to the area of quadrilateral ABCE?

Hello Guest!

\(A_{ADE}=\frac{10\cdot 1}{2}=5\\ A_{ABCE}=6\cdot 10-5=55\\ \color{blue}\frac{A_{ADE}}{A_{ABCE}}=\frac{5}{55}=\frac{1}{11}\)

  !

What is the volume of this sphere?

Hello Guest!

\(r_K=\frac{12}{2}=6\\ V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi \cdot 6^3=\color{blue}904.8\)

  !

3C2 * 0.6^2 * 0,4 = 3*0.36*0.4 = 0.432

Thanks once again CPhill!!!

-Vinculum

We have an example of the ambiguous case = SSA

Using the Law of Sines

sin B / 10  = sin C / 9

sin B /10 = [sqrt (3) /2] / 9

sin B = 10 sqrt (3) /  18 = (5/9)sqrt 3 =  

arcsin [ (5/9)sqrt 3 ] = B  ≈  74.2°  or    B  ≈ 105.8°

So

So , in one case, C =  180  - 60  - 74.2   ≈ 45.8°

So...let's figure a2 first

a2 / sin (45.8)  = 9 /sin C

a2 / sin (45.8) =  9 / [ sqrt (3) / 2 ]

a2 =sin (45.8) * 18 / sqrt 3  ≈  7.45 

And in the second case

C = 180 -60 - 105.8   ≈  14.2°

So....by the Law of Sines again we can find a1 as

a1 / sin (14.2) = 18/sqrt 3

a1=  sin (14.2) * 18 /sqrt 3 ≈  2.55

{a1 , a2}  = {2.55 , 7.45}

1 + 4

4 + 1

3 + 2 

2 + 3 

6 + 9

9 + 6

7 + 8

8 + 7

11 + 4

4 + 11

3 + 12

12 + 3

10 + 5

5 + 10

                     Can't roll the red ones AND the black ones above each red..... the dice are marked differently......

                          first answerer missed    11 - 4      so correct answer is    7 out of 36      or   7/36 

Welcome  !!!!

Law of Sines

sin (pi/6) / (3x)  = sin B / ( x )             simplify

(1/2) / 3  = sin B

sin B  = 1/6

12 sin (B )  = 2

Since  sin B  = 1/6         then the altitude must be  1   and  x  must be 2   

Using the Law of Sines again

sin (pi /6) / (3x) =  sin (C) /AB

(1/2) /  6  =  sin (C) / AB

(1/12) = sin (C) / AB

sin C  =  AB / 12

So

12 sin C   =  AB