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idk, probably some advanced method of coding 

Thanks, CPhill!!!!!!!!!

-Vinculum

Law of Sines

sin ( A ) / 13  =  sin C / 24

sin ( A) / 13  = sin ( 2A) / 24

sin (A) / 13  = [ 2sin (A) cos (A)] / 24

1/13  = cos ( A  )/ 12

12/13 = cos ( A )

sin (A)  =  sqrt [ 13^2 - 12^2] / 13  =  5/13

sin (C)  =  sin (2A)  =  2sin(A)cos(A)  =  2 (5/13) (12/13)  = 120 / 169

Someone calcuated 120 composite numbers only having 2 prime factors (including square numbers)

https://web2.0calc.com/questions/prime-factors

You can use this as well if needed:

https://web2.0calc.com/questions/please-help_56600

“positive integers less than 100” are 1–99.

For the result to be a multiple of 3, only one of the numbers chosen has to be a multiple of 3.

There is a 66/99 (2/3) chance that the first number isn't a multiple of 3.

There is a 65/98 chance that the second number isn't a multiple of 3 as it cannot be the same one already chosen.

The chance of neither being a multiple of 3 is 2/3 x 65/98 = 1/3 x 65/49 = 65/147

The chance of one of them being a multiple of three (and therefore the two multiplied together being a multiple of 3) is 1–65/147 = 82/147 or approximately 55.8%"

hit x hit x miss  =  .60 x .60 x .40  =  .144

hit x miss x hit  =  .60 x .40 x .60  =  .144

miss x hit x hit  =  .40 x .60 x .60  =  .144

Adding these together:                     .432

Used the exact method as geno3141 in the question linked below: 

https://web2.0calc.com/questions/help_69037

Hello this question has been answered by Dragan and a few others:

Please take a took...

https://web2.0calc.com/questions/more-hw-please-help

If you see anything wrong with it please let me know so I can assist you with this question.

\(14x-13 =8x+5\)

\(14x-8x=13+5\)

\(6x=18\)

\(x=3\)

Substituting that back ta PQ

\(14(3)-13 = 29\)

\(PQ=29\)

Excellent, catmg   !!!!

There are 14 red marbles and 7 blue marbles in the bag. 

The probability of getting a red marble is \(2 \over 3\). The probability of getting a blue marble is \(7 \over 20\), because we already took 1 marble. 

Thus, the probability is \({2 \over 3} \times {7 \over 20} = \color{brown}\boxed{7 \over 30}\)

sec 4x  =  csc (x - 60)

The secant and co-secant  are co-functions   ....so.....this means  that

4x + (x - 60)  = 90

5x  = 150

x = 30

We have a rectangular prism

The volume  is  (base area ) * (height) =  

( EF * EH) * (EA)  =

( 4 * 5 ) * ( 5)  = 

100 units^3

Yeah, I wasn't sure if that was the question or not, and to not cause confusion I didn't post it.

Thanks, guys   !!!!

Yep, I was gonna say the same thing !!!!!

Also if you would like a different method of approaching the problem, Melody and CPhill have answered it in the link below:

https://web2.0calc.com/questions/what-is-the-area-of-the-trapezoid-shown-express-your-answer-in-simplest-exact-form

Sorry, this site is too addicting...

Also, it's not about getting here "first"... It's about helping people learn. 

I am so sure this has been posted, but the picture was gone, so I'm just gonna do it. 

First, we need to find the height and the bases.

How?. We can see that there is a 30-60-90 triangle!

Then, we can find the height. It is \(\sqrt{3}\)(You know this right?) Then the BIG base is 2+1+1 = 4.

Then using the formula, you get \(\frac{2+4}{2}\sqrt{3}\) so the answer is \(3\sqrt{3}\)

Hope this helped!

grade 10? 

There can be: 

0 girls + 7 boys: \({4 \choose 0} \times {8 \choose 7} = 8\)

1 girl + 6 boys: \({4 \choose 1} \times {8 \choose 6} = 112\)

2 girls + 5 boys: \({4 \choose 2} \times {8 \choose 5} = 336\)

3 girls + 4 boys: \({4 \choose 3} \times {8 \choose 4} = 280\)

4 girls + 3 boys: \({4 \choose 4} \times {8 \choose 3} = 56\)

Adding everything up, there can be \(\color{brown}\boxed{792}\) committees.