The overlap area is \(8 \times 8 = \color{brown}\boxed{64}\) inches squared.
Similar problem, use the same method heureka used: https://web2.0calc.com/questions/pls-help-i-don-t-know-how-to-do-this
All circles are similar......the scale factor of S to L = 1/2
Area of S =
Area of L * scale factor^2 =
(pi * 8^2) * (1/2)^2 =
64 pi / 4 =
16 pi ≈
50.24 mm^2
Note that because we are squaring things, there will be positive and negative solutions that always cancel out to \(\color{brown}\boxed{0}\)
Hint: The sum of the angles is 90 degrees.
N = what Noah sold
N + 45 = what Max sold
N - 40 = what John sold
N + N + 45 + N - 40 = 350
3N + 5 = 350
3N = 350 - 5
3N = 345
N = 345 / 5 = 69
N - 40 = 69 - 40 = 29 = what John sold
https://web2.0calc.com/questions/geometry_24420
That's incorrect
catmg's answer:
(x)^2 + (x+y)^2 = (x + 2y)^2 (this is the pythagreon theorum)
x^2 + x^2 + y^2 + 2xy = x^2 + 4y^2 + 4xy
2x^2 + y^2 + 2xy = x^2 + 4y^2 + 4xy
x^2 = 3y^2 + 2xy
So we're looking for xy, and we could solve for it, but let's just say x = 1 for simplicity.
1^2 = 3*y^2 + 2(1)y
1 = 3y^2 + 2y.
y = 1/3.
So y/x = 1/3/1 = 1/3.
I hope this helped. :)))
=^._.^=
here's link
https://web2.0calc.com/questions/right-triangle_21
im sorry, i need to control myself. I was just kinda surprised by the simplexity of this question. Compared to others...
The sum of all possible values of z is 66.
Area of APB = (1/2) 4^2 = 8
BD = 2*BP = 2*4 = 8
And snce angle DBC = 45°, then BD = Dc
So
Area of BDC = (1/2)(8^2) = 32
Area of ABCDP =
8 + 32 =
40
x^2 + 13x+ 30 = (x + 10) (x + 3)
x^2 + 6x + 9 = (x + 3) ( x + 3)
a + b + c =
10 + 3 + 3 =
16
-2
( 3x + 2) ( 3x - (-2) ) =
(3x + 2) (3x + 2) =
(3x + 2)^2
*****
xyz = 682.
Number of red marbles = 3.
Number of blue marbles = 3
Total number of marbles=3+3+6=12.
Probability number of red and blue marbles out of total number.
=> 6/12
or 0.5
oops my bad. man my eyes need better contacts. you are correct mate.
CPhill and melody, and ep and a bunch of other great mathematicians are all gods.
CORRECTO MUNDO!!!
i^5 + i^(-25) + i^45
i^5 = i
i^45 = i
i^(-25) = 1 / (i^25) = 1 / i^25 = ( 1 * i^3 ) / ( i^25 * i^3) = -i / (i^28) = -i /1 = -i
( i ) + ( -i ) + ( i ) =
i
CPhill's answer here:https://web2.0calc.com/questions/help_9744
Probability of two kings = C(4,2) / C(52, 2)
Probability of at least one ace = 1 - P (no aces) = 1 - C(48, 2) / C(52, 2)
So......total probability is
[ C(4,2)/C(52, 2) ] + [ 1 - C(48,2) / C(52,2)] = 2 / 13
thx CPhill (the pro)
sumfor(n, 1, 100, (3*n^2 +5*n +2))==1,040,500
