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5 times 2 is 10 because 5 pluse 5 is 10

365!  =  365 x 364 x 363 x ... x 332 x 331 x 330!

(365 - 35)!  =  330!

So:  365! / 330!  =  365 x 364 x 363 x ...x 332 x 331  (because the 330! in the numertor cancels the 330! in the denominator.

You are left with: [ 365 x 364 x 363 x ...x 332 x 331 ] / 365 ^ 35

Which would be:  365/365 x 364/365 x 363/365 x ... x 331/365

Now with patience, your answer will be ...

If you have lim(x→4) for some function, f(x)

and you want to change the limit to x→0, change the function  from f(x) to f(x-4) 

As an example:  lim(x→4) x² - 8   would change to:  lim(x→0) (x-4)² - 8 

$${{\mathtt{5}}}^{{\mathtt{a}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{b}}} = {{\mathtt{5}}}^{\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right)}$$

$${{\mathtt{5}}}^{{\mathtt{3}}} = {\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}$$

$${{\mathtt{5}}}^{-{\mathtt{3}}} = {\frac{{\mathtt{1}}}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}\right)}}$$

$${{\mathtt{5}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{-{\mathtt{3}}} = {{\mathtt{5}}}^{\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{3}}\right)}$$  = $${{\mathtt{5}}}^{{\mathtt{0}}}$$

$${{\mathtt{5}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{-{\mathtt{3}}} = {\frac{{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}}{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}}\right)}}$$ = 1

$${{\mathtt{5}}}^{{\mathtt{0}}} = {\mathtt{1}}$$

2

the amplitude is 2

2 236 000  -  17 740x  =  3 500 000

First, subtract 2 236 000 from both sides:

               - 17 740x  =  1 264 000

Now, divide both sides by -17 740

                            x  =  1 264 000 / -17 740  =  -71.3  (approx)

If you use combinations:  (2x + 5) ^ 5:

5nCr5·(2x)^5·(5)^0  +  5nCr4·(2x)^4·(5)^1  +  5nCr3·(2x)^3·(5)^2  +      5nCr2·(2x)^2·(5)^3  + 5nCr1·(2x)^1·(5)^4  +  5nCr0·(2x)^0·(5)^5

= 1·32x^5·1  + 5·16x^4·5  +  10·8x^3·25  +  10·4x^2·125  +  5·2x·625  +  1·x^0·3125

=  160x^5  +  400x^4  +  2000x^3  +  5000x^2  +  6250x + 3125

The distance formula is:  d  =  √[ (x2 - x1)² + (y2 - y1)² ]

It makes no differnce which point you call (x1, y1) and which point you call (x2, y2).

If  (x1, y1) = (-3, -2)  and  (x2, y2) = (7, -6),

then  x1 = -3    y1 = -2    x2 = 7    and     y2 = -6

Substituting:                d  =  √[ (7 - -3)² + (-6 - -2)² ]

                                   d  =  √[ (10)² + (-4)² ]

                                   d  =  √[ 100 + 16 ]

                                   d  =  √[ 116 ]

                                   Reduce, if you wish.

Finding the difference is subtracting:

              1658  -  5000  =  -3342.

Since the statement doesn't tell which way to subtract, the answer could be  5000 - 1658  =  3342.

(√x)^6  =  √x·√x·√x·√x·√x·√x

            =  (√x·√x)·(√x·√x)·(√x·√x)

            =  (x)·(x)·(x)

            =  x^3

A faster way is to write  √x  as  x^(1/2)               (Because a square root is a number to the 1/2 power.)

Then  (√x)^6  =  ( x^(1/2) )^ 6  =  x^3             (Because, to simplify a problem that is a power to a power,

                                                                         multiply the two powers together:  1/2 x 6  =  3.)

The distance formula is:  d  =  √[ (x2 - x1)² + (y2 - y1)² ]

It makes no differnce which point you call (x1, y1) and which point you call (x2, y2).

If  (x1, y1) = (-6, 5)  and  (x2, y2) = (-1, -7),

then  x1 = -6    y1 = 5    x2 = -1    and     y2 = -7

Substituting:                d  =  √[ (-1 - -6)² + (-7 - 5)² ]

                                   d  =  √[ (5)² + (-12)² ]

                                   d  =  √[ 25 + 144 ]

                                   d  =  √[ 169 ]

                                   d  =  13

7 1/8  =  7 + 1/8

To find 2(7 + 1/8) multiply the 2 x 7 and the 2 x 1/8:  2 x 7  =  14  and  2 x 1/8  =  2/8

So, the answer is 14 2/8  =  14 1/4

4/5 is in common fraction form.

To find decimal divide 4 by 5 to get 0.8.

y  =  0.25(0) - 4  =  0 - 4  =  -4

y  =  -2x - 1

Replace the 'x' with a '1':  y  =  -2(1) - 1  =  -2 - 1  =  -3. 

This is the value that you wanted for y, so yes, it is a solution!

126  =  2 x 3 x 3 x 7

264  =  2 x 2 x 2 x 3 x 11

The greatest common factor is the largest number that divides evenly into both; you can use only those factors which are in each, there is only one 2 in each, one 3 in each, and the 7 and the 11 isn't in both, so you ignore them.

It will have one 2 and one 3:  2 x 3  =  6

Change 5 1/3 into 16/3

(1/4)(3x - 16) + (1/4)x = 16/3

Multiply all terms by 4:

3x - 16 + x = 64/3

Multiply all tlerms by 3:

9x - 48 + 3x = 64

Simplify 9x + 3x:

12x - 48  =  64

Add 48 to both sides:

12x  =  112

Divide both sides by 12:

x  =  112/12  =  9 1/3

28  =  1 + 3(v - 7)^(2/3)

Subtract 1 from both sides:

27  =  3(v - 7)^(2/3)

Divide both sides by 3:

9  =  (v - 7)^(2/3)

Since an exponent of 2/3, means "the cube root of the square", cube both sides:

729  =  (v - 7)^2

Find the square root of both sides:

27  =  v - 7

Add 7 to both sides:

34  =  v

On a graph, the equation  y = x - 1  becomes a straight line that has a y-intercept of -1 (the point (0,-1)), and from there moves to the upper right at a 45° angle, through the points (1,0), (2,1), (3,2), ...

The equation  y = -x + 5  becomes a straight line that has a y-intercept of 5 (the point (0,5) ), and from there moves to the lower right at a -45° angle, through the points (1,4), (2,3), (3,2), ...

Since i² = -1, 1 + i² = 1 + (-1) = 0.

What's the question?

1585 x 2.5 x 2.5 = 9906.25.

If the tiles are measured in feet, they will cover 9906.25 square feet. 

If the tiles are measured in inches they will cover 9906.25 square feet or 68.8 square feet.

If the ties are measured in yards, they will cover 9906.25 square yards or 89.156/25 sqiare feet.

The probability of getting 2 wins in ten chances with a 20% probability of success  is 0.032 (approximately).

so i can ask for help

are u crazy that is esiey